.012 J is going to be your answer
Answer:
10,000 eV
Explanation:
According to the law of conservation of energy, the kinetic energy gained by the electron is equal to its change in electric potential energy:
where:
K is the kinetic energy of the electron
is the magnitude of the charge of the electron
is the potential difference through which the electron has been accelerated
For this electron in the TV, we have
Therefore, the kinetic energy of the electron in electronvolts is
Answer:
#_photon = 5 10²⁰ photons / s
Explanation:
For this exercise let's calculate the energy of a single quantum of energy, use Planck's law
E = h f
c= λ f
E = h c / λ
λ= 1000 nm (1 m / 109 nm) = 1000 10⁻⁹ m
Let's calculate
E₀ = 6.6310⁻³⁴ 3 10⁸/1000 10⁻⁹
E₀ = 19.89 10⁻²⁰ J
This is the energy emitted by a photon let's use a proportions rule to find the number emitted in P = 100 w
#_photon = P / E₀
#_photon = 100 / 19.89 10⁻²⁰
#_photon = 5 10²⁰ photons / s
