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3 years ago

11

WILL AWARD BRAINLIEST+THANKS+5 STARS!!

2 answers:

kozerog [31]3 years ago

8 0

First of all, we know that the 6-sider dice has 6 numbers that label from 1 to 6, and there are five number that are not 5(1,2,3,4,6), so
P(not 5):5/6 or about 0.83 or 83%. Hope it help!

Elza [17]3 years ago

3 0

Sample space ={1,2,3,4,5,6,} =6 possible outcome
P(getting 5) = 1/6
P(NOT getting 5) = 1-1/6 = 5/6 = 0.834
Or NOT getting 5 means GETTING 1,2,3,4,6 = 5 favorable outcome &
P(NOT getting 5) = / =

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Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

so

Let

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y-----> size of the sample space

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In this problem

<em>The probability of choose a blue card is </em>

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substitute

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<em>The probability of choose a green card is </em>

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substitute

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<em>The probability of choose a red card is </em>

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substitute

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