I think that the wavelengths of an incoming solar radiation are shorter than the wavelengths of reradiated heat. This is because the incoming solar radiation to the surface of the earth is in the utraviolet (short) to near infrared (long) wavelength bands. After absorption has taken place, surfaces reradiate heat energy back to the atmosphere at long wavelength infrared.
Answer:
Explanation:
Given that the grand stone has initial angular velocity of
w(ini)= 6rad/
And it has a final angular velocity of
w(fin)=12.20rad/sec
Time taken is t=16s
Using equation of angular motion
To get angular acceleration (α)
w(fin)=w(ini)+αt
12.20=6+16α
16α=12.20-6
16α=6.2
α=6.2/16
α=0.3875rad/sec²
The angular acceleration is 0.39rad/s²
Angle that he turn using
w(fin)²=w(ini)²+2αθ
12.2²=6²+2×0.3875θ
12.2²-6²=0.775θ
0.775θ=112.84
Then, θ=112.84/0.775
θ=145.6radian
The angular displacement is 145.6rad
A). It takes air in from outside the body.
Answer:
v = 16.11 m / s
Explanation:
For this exercise we must use the principle of conservation of energy. We set a reference system on the part of the platform without elongation
starting point. When the spring is compressed
Em₀ = K_e + U = ½ k x² + m g x ’
final point. The point where it leaves the platform
Em_f = K = ½ m v²
energy is conserved
Em₀ = Em_f
½ k x² + m g x ’= ½ m v²
v² = 
x² + g x
let's calculate
v² = 
1.25² + 9.8 1.25
v² = 247.159 + 12.25 = 259.409
v = 16.11 m / s
