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zmey [24]
3 years ago
15

The acceleration due to gravity at the surface of a planet depends on the planet's mass and size; therefore other planets will h

ave accelerations due to gravity different from 9.8 m/s2. imagine an astronaut stands on an alien planet, which has no atmosphere, and throws a rock with a speed of 7.45 m/s in the horizontal direction, releasing it at a height of 1.40 m above the surface of the planet. the rock hits the surface a horizontal distance of 8.90 m from the astronaut. find the magnitude of the acceleration due to gravity on this alien planet.
Physics
1 answer:
Cloud [144]3 years ago
5 0
Chaff has also written about his book of Mormon that is not true to say this but it doesn't have the
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A 2-Newton upward net force is being applied to a 10-kg object. What is the magnitude of the upward
Colt1911 [192]
Acceleration in m/s^2 = 2/10 = 0.2 m/s^2
7 0
3 years ago
D=1/2at^2 <br> solve for a
nignag [31]

Answer:

a = 2d / t²

Explanation:

d = ½ at²

Multiply both sides by 2:

2d = at²

Divide both sides by t²:

a = 2d / t²

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3 years ago
A typical oil control ring consists of _______ separate part(s).
azamat
<span>A. three</span><span>

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2 years ago
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7. Imagine you are pushing a 15 kg cart full of 25 kg of bottled water up a 10o ramp. If the coefficient of friction is 0.02, wh
pentagon [3]

Answer:

The frictional force needed to overcome the cart is 4.83N

Explanation:

The frictional force can be obtained using the following formula:

F= \mu R

where \mu is the coefficient of friction = 0.02

R = Normal reaction of the load = mgcos\theta = 25 \times 9.81 \times cos 10 = 241.52N

Now that we have the necessary parameters that we can place into the equation, we can now go ahead and make our substitutions, to get the value of F.

F=0.02 \times 241.52N

F = 4.83 N

Hence, the frictional force needed to overcome the cart is 4.83N

4 0
3 years ago
An student in a swimming pool weighs 450 N and in a regular balance out of the swimming pool weighs 700 N. What is the value of
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