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Novay_Z [31]
4 years ago
8

Is 250 g higher than 100 g in science

Physics
2 answers:
Kitty [74]4 years ago
6 0
(Rhetorical question of you to ask but...) Yes 250 g is higher / greater than 100 g in science.
polet [3.4K]4 years ago
5 0
Its the same thing. Is 250 grams more then 100 grams
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The chemical formula for water, H2O, means that each water molecule contains
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The chemical formula for water, H2o means that each water molecule contains one oxygen atom and two hydrogen atoms. This is the formula for water which has a liquid form, a solid form as ice, and also a gaseous form as water vapor. 
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tangare [24]

Answer:

the answer from my side is both vertical and horizontal

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The fast server in women's tennis is Venus Williams, who recorded a serve of 130 mi/h (209 km/h) in 2007 If her racket pushed on
Darina [25.2K]
209 km/h = 58.0 m/s

2as = v² - u²
Assuming the ball started from rest,

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7 0
3 years ago
Determine an appropriate size for a square cross-section solid steel shaft to transmit 260 hp at a speed of 550 rev/min if the m
Phantasy [73]

Answer:46.05 mm

Explanation:

Given

Power=260\ hp\approx 260\times 746=193.96\ KW

speed N=550\ rev/min

allowable shear stress (\tau )_{max}=15\ kpsi\approx 103.421\ MPa

Power is given by

P=\frac{2\pi NT}{60}

193.96=\frac{2\pi 550\times T}{60}

T=3367.6\ N-m

From Torsion Formula

\frac{T}{J}=\frac{\tau }{r}-----1

where J=Polar section modulus

T=Torque

\tau=shear stress

For square cross section

r=\frac{a}{2}

where a=side of square

J=\frac{a^4}{6}

Substituting the values in equation 1

\frac{3376.6}{\frac{a^4}{6}}=\frac{103.421\times 10^6}{\frac{a}{2}}

a=0.04605\ m

a=46.05\ mm

7 0
3 years ago
Two wheels roll side-by-side without sliding, at the same speed. The radius of wheel 2 is one-half (1/2) the radius of wheel 1.
Lemur [1.5K]

Answer:

w'=(1/2)w

Explanation:

In order to calculate the angular velocity of the second wheel, you use the following formula:

\omega=\frac{v}{r}      (1)

v: speed of the wheel 1 = speed of the wheel 2

r: radius of the wheel 1

For the second wheel you have:

r'=2r

You replace this value of r' in the following equation:

\omega'=\frac{v}{r'}=\frac{v}{2r}=\frac{1}{2}\frac{v}{r}=\frac{1}{2}\omega\\\\\omega'=\frac{1}{2}\omega

The angular velocity of the second wheel is one half of the angular velocity of the first wheel

6 0
3 years ago
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