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Novay_Z [31]
3 years ago
8

Is 250 g higher than 100 g in science

Physics
2 answers:
Kitty [74]3 years ago
6 0
(Rhetorical question of you to ask but...) Yes 250 g is higher / greater than 100 g in science.
polet [3.4K]3 years ago
5 0
Its the same thing. Is 250 grams more then 100 grams
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A man stands on top of a cliff and shouts.
satela [25.4K]

\small\bf \: let \: the \: distance \: of \: the \: man \: from \: the \: cliff \: be \: x

\small\bf \: thus \: time \: taken \: by \: sound \: to \: hit \: the \: cilff \: and \: return =  \frac{2x}{v}  = 1

\bf \to \: x =  \frac{320}{2} m = 160m

\small \bf \: thus \: the \: distance \: between \: the \: cliffs \:  = 160m \times 2 = 320m

8 0
3 years ago
A woman is running around a playground while keeping an eye on her child who is on a swing set. The child is going back and fort
Nutka1998 [239]

Answer:

(a) 1500 m

(b) 2827.43m

Explanation:

Given that the time for one cycle of the swing is 1 s

The radius of the swing, R= 3.0m

The angle covered, \theta, by each swing is a quarter of the circle. i.e.

\Theta=\frac {\pi}{2}

Speed of running of women =5 m/s.

Time of running = 5 minutes= 5 x 60 secondes= 300 s.

(a) As distance= (speed) x (time)

So, the required distance= 5 x 300 m= 1500 m.

(b) As there are two swings in one cycle, so, the distance covered in one swing is the length of the circular shown in the figure.

As arc length, l= \theta R, where \theta is the angle, in radian, subtended by the arc at the center, and R is the radius of curvature of the arc.

So, the distance covered by the child in 1 swing = \frac {\pi}{2}\times 3 m=\frac{3\pi}{2}m.

In 1 cycle, there are 2 swings, so distance covered in 1 cycle = 3 \pi m.

Now, in 1 second there is 1 cycle, so in 5 minutes there will be 300 cycles.

So, the total distance covered by the child

= 3\pi\times 300 m= 2827.43 m.

3 0
3 years ago
What aspect of speech sound is the primary factor in determining if one perceives the /ba/ sound or the /pa/ sound?
nignag [31]
The answer is voice onset time. It is a part of the production of stop consonants. Its definition is the length of time that passes between the release of a stop consonant and the start of the voicing and the vibration of the vocal folds.
3 0
2 years ago
A mixture of gas expands from 0.03m³ to 0.06m³ at constant pressure of 1MPa & absorbs energy of 84 J. Calculate the change i
leonid [27]

Answer:54 kj

Explanation:P1 = P2 = 1000 kPa

1Q2 = 84 kJ

1W2 = P1 (V2 – V1)

= 1000 (0.06 – 0.03) = 30 kJ

1Q2 = 1W2 + 1U2

U2 – U1= 1Q2 – 1W2 = 84 – 30 = 54 kJ

4 0
2 years ago
A material used for electrical wiring must have
lapo4ka [179]
A certain amount of Conductivity
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3 years ago
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