If you pick up and carry a piece of heavy furniture which type of friction do you have with the floor

? What is the magnitude of force required to accelerate a car of mass 1.7 × 103 kilograms by 4.75 meters/second2

KIM [24]

f=ma

f=175.1*4.75m/s

f= 831.725N

4 0

3 years ago

Read 2 more answers

Lasers can be constructed that produce an extremely high intensity electromagnetic wave for a brief time—called pulsed lasers. T

MAVERICK [17]

Explanation:

It is given that,

Maximum electric field, $E=10^{11}\ V/m$

Time taken, $t=1\ ns=10^{-9}\ s$

(a) Maximum magnetic field, $B=\dfrac{E}{c}$

$B=\dfrac{10^{11}\ V/m}{3\times 10^8\ m/s}$

B = 333.33 T

(b) Intensity of beam, $I=\dfrac{E^2}{2\mu_o c}$

$I=\dfrac{(10^{11})^2}{2\times 4\pi \times 10^{-7}\times 3\times 10^8}$

$I=1.32\times 10^{19}\ W/m^2$

(c) Energy delivered by the pulse, $E=I\times A\times t$

$E=1.32\times 10^{19}\times 10^{-6}\times 10^{-9}$

E = 13200 J

Hence, this is the required solution.

8 0

3 years ago

An airplane is flying in a horizontal circle at a speed of 100 m/s. The 80.0 kg pilot does not want the centripetal acceleration

Tema [17]

Answer:

The force will be "5,488". A further solution is provided below.

Explanation:

The given values are:

speed,

v = 100m/s

mass,

m = 80 kg

acceleration,

a = 7

Now,

Radius will be:

⇒ $r=\frac{v^2}{ac}$

⇒ $=\frac{(100)^2}{7\times 9.8}$

⇒ $=\frac{10000}{68.6}$

⇒ $=145.77$

Force will be:

⇒ $F=m\times ac$

⇒ $=80\times 68.6$

⇒ $=5488$

3 0

3 years ago

A body moving with an initial velocity of 30m/s accelerates uniformly at the rate of 10m/s . what is the distance covered during

nikdorinn [45]

Answer:

The distance covered by the body is, S = 800 m

Explanation:

Given data,

The initial velocity of the body, u = 30 m/s

The acceleration of the body, a = 10 m/s²

Let the time period of travel be, t = 10 s

Using the II equations of motion,

S = ut + ½ at²

Substituting the given values,

S = 30 x 10 + ½ x 10 x 10²

S = 800 m

Hence, the distance covered by the body is, S = 800 m

5 0

3 years ago

Indiana Jones is in a temple searching for artifacts. He finds a gold sphere with a radius of 2 cm sitting on a pressure sensiti

Vlad1618 [11]

Answer:

Volume of Sand = 0.4 m³

Radius of Sand Sphere = 0.46 m

Explanation:

First we need to find the volume of gold sphere:

Vg = (4/3)πr³

where,

Vg = Volume of gold sphere = ?

r = radius of gold sphere = 2 cm = 0.02 m

Therefore,

Vg = (4/3)π(0.2 m)³

Vg = 0.0335 m³

Now, we find mass of the gold:

ρg = mg/Vg

where,

ρg = density of gold = 19300 kg/m³

mg = mass of gold = ?

Vg = Volume of gold sphere = 0.0335 m³

Therefore,

mg = (19300 kg/m³)(0.0335 m³)

mg = 646.75 kg

Now, the volume of sand required for equivalent mass of gold, will be given by:

ρs = mg/Vs

where,

ρs = density of sand = 1602 kg/m³

mg = mass of gold = 646.75 kg

Vs = Volume of sand = ?

Therefore,

1602 kg/m³ = 646.75 kg/Vs

Vs = (646.75 kg)/(1602 kg/m³)

Now, for the radius of sand sphere to give a volume of 0.4 m³, can be determined from the formula:

Vs = (4/3)πr³

0.4 m³ = (4/3)πr³

r³ = 3(0.4 m³)/4π

r³ = 0.095 m³

r = ∛(0.095 m³)

4 0

3 years ago