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marusya05 [52]
4 years ago
12

*Please Help!* (There are more than two answers!)

Physics
2 answers:
CaHeK987 [17]4 years ago
7 0
B and C are the answers
Bas_tet [7]4 years ago
3 0

Answer:

B and C

Explanation:

The formula:

P = W / t  (where P is power; W is work done; t is time)

Can be written in different ways, depending on what value you are trying to find. For example, if you have power, and time, but you want to calculate work, the formula can be rearranged to look like this:

W = P x t

It can also be rearranged to calculate for time:

t = W / P

Hence, the formula has three arrangements to calculate different values.

P = W / t ; W = P x t ; t = W / P

Comparing these formulas to the options given, it can be seen that options B and C are correct.

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A car drives down the highway at 30 m/s. The speed limit increases, and the car accelerates to 33 m/s over a displacement of 70
MrMuchimi

Answer:

the driveway takes about 243 meters per second for cfar to accelerate

Explanation:

7 0
3 years ago
Convert 285,000 milliliters to decaliters.​
Rudiy27
The answer is 28.5 decaliters. Hope this helps
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A stuntman drives a car with a mass of 1500 kg on a drawbridge. The car accelerates with a constant force of 10,000 N. While he
Viktor [21]

Answer:

1.77 m/s^2

Explanation:

There are two forces acting on the car along the direction parallel to the incline:

- The driving force of 10,000 N, which pushes forward

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W_p = mg sin \theta=(1500 kg)(9.8 m/s^2)( sin 30^{\circ})=7350 N

So now we can apply Newton's second law to find the acceleration of the car:

F-W_p = ma\\a=\frac{F-W_p}{m}=\frac{10000 N-7350 N}{1500 kg}=1.77 m/s^2

7 0
3 years ago
What is the final temperature when 50 g of water at 20°c is mixed with 75 g of water at 60°c
tatyana61 [14]
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4 0
4 years ago
A cylindrical tungsten filament 16.0 cm long with a diameter of 1.00 mm is to be used in a machine for which the temperature wil
KonstantinChe [14]

Answer:

Explanation:

Resistance of the tungsten wire

R = resistivity x length / cross sectional area

= \frac{5.25\times10^{-8}\times16\times10^{-2}}{3.14\times(.5\times10^{-3})^2}

= 107 x 10⁻⁴ ohm

Resistance at 120 degree can be obtained from the following formula

R_t = R_0( 1 + \alpha\times t )

R_t = 107\times10^{-4}( 1 + .0045\times 100)

= 155.15 x 10⁻⁴ ohm

= 160 x 10⁻⁴ ohm ( rounding off to two syg fig )

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potential diff = 12.5 x 155.15 x 10⁻⁴ V

=  0 .1939 V

= .19 V

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= .1939 / 16 x 10⁻²

= 1.2 N / C

4 0
3 years ago
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