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marusya05 [52]
3 years ago
12

*Please Help!* (There are more than two answers!)

Physics
2 answers:
CaHeK987 [17]3 years ago
7 0
B and C are the answers
Bas_tet [7]3 years ago
3 0

Answer:

B and C

Explanation:

The formula:

P = W / t  (where P is power; W is work done; t is time)

Can be written in different ways, depending on what value you are trying to find. For example, if you have power, and time, but you want to calculate work, the formula can be rearranged to look like this:

W = P x t

It can also be rearranged to calculate for time:

t = W / P

Hence, the formula has three arrangements to calculate different values.

P = W / t ; W = P x t ; t = W / P

Comparing these formulas to the options given, it can be seen that options B and C are correct.

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A dolphin leaps out of the water at an angle of 36.6° above the horizontal. The horizontal component of the dolphin's velocity i
Mariana [72]

Answer:

Explanation:

Given

Dolphin leaps out an angle \theta =36.6^{\circ}

Horizontal component of dolphin velocity u_x=7.87\ m/s

Suppose u is the launch velocity of dolphin

therefore u\cos \theta =u_x---1

and vertical velocity u_y=u\sin \theta ----2

divide 1 and 2 we get

\tan \theta =\frac{u_y}{u_x}

u_y=u_x\tan \theta

u_y=7.87\cdot \tan (36.6)

u_y=5.84\ m/s

4 0
2 years ago
Which of these describes Kepler’s third law of orbital motion?(1 point)
Nadusha1986 [10]

Answer:

T2 ∝ a3

Explanation: took the quick check

4 0
1 year ago
2. How many grams of water can be heated from 20.0°C to 75°C using<br><br><br> 12500.0 Joules?
bogdanovich [222]

Answer:

Grams of water can be heated from 20.0°C to 75°C using  12500.0 Joules = 54.3 g

Explanation:

Heat required to increase temperature

                 H = mcΔT

m = mass of material

C = specific heat of material

ΔT = Change in temperature.

Here we need to find  how many grams of water can be heated from 20.0°C to 75°C using  12500.0 Joules

That is

            H = 12500 J

            Specific heat of water, C = 4186 J/kg°C

            ΔT = 75 - 20 = 55

Substituting

            12500 = m x 4186 x 55

              m = 0.0543 kg

              m = 54.3 g

Grams of water can be heated from 20.0°C to 75°C using  12500.0 Joules = 54.3 g

3 0
3 years ago
Express the vector R<br> B<br> in terms of A, B, C, and Ď, the edges of a<br> parallelogram.
Vadim26 [7]

Answer:

R=0.5B+0.5C+2A+D

Explanation:

By the triangular law of vector addition

vector R= vector B- vector D

As A,B,C,D are edges of the parallelogram,

A is parallel to D but opposite in direction.

Therefore

A = (-D);A//D;

2A=-2D

B is parallel to C and in same direction.

B//C\\B=C\\

0.5B=0.5C\\

R= B-D;\\R= 0.5B+0.5B-D;\\R=0.5B+0.5C-D;\\R=0.5B+0.5C-2D+D;\\R=0.5B+0.5C+2A+D;

7 0
2 years ago
A diver shines light up to the surface of a flat glass-bottomed boat at an angle of 30° relative to the normal. If the index of
son4ous [18]

Answer:

<h2>35</h2>

Explanation:

According to snell's law which states that the ratio of the sin of incidence (i) to the angle of refraction(n) is a constant for a given pair of media.

sini/sinr = n

n is the constant = refractive index

Since the diver shines light up to the surface of a flat glass-bottomed boat, the refractive index n = nw/ng

nw is the refractive index of water and ng is that of glass

sini/sinr = nw/ng

given i = 30°, nw = 1.33, ng = 1.5, r = angle the light leave the glass

On substitution;

sin 30/sinr = 1.33/1.5

1.5sin30 = 1.33sinr

sinr = 1.5sin30/1.33

sinr = 0.75/1.33

sinr = 0.5639

r = arcsin0.5639

r ≈35°

angle the light leave the glass is 35°

7 0
3 years ago
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