An electron moves with velocity v⃗ =(5.9i−6.4j)×104m/s in a magnetic field B⃗ =(−0.63i+0.65j)T. Determine the z-component of the
force on the electron. Fz=?
1 answer:
Answer:
Explanation:
Force on the electron = q ( v x B )
q = - 1.6 x 10⁻¹⁹
v = (5.9i−6.4j)×10⁴
B = (−0.63i+0.65j)
v x B = (5.9i−6.4j)×10⁴ x (−0.63i+0.65j)
= (3.835 - 4.032 ) x 10⁴ k
= - 1970 k
Force on the electron = q ( v x B )
= - 1.6 x 10⁻¹⁹ x -1970 k
= 3.152 x 10⁻¹⁶ k
z-component of the force on the electron
Fz = 3.152 x 10⁻¹⁶ N
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