Since you have not included the figures with the diagrams to select the right answer, I am going to explain the main differences that lead you to differentiate electrochemical cells.
There are four important terms needed to identify the electrochemical cells: electrolysis, electrochemical cells, electrolitc cells and voltaic cells.
1) Electrochemical cell: is a device that uses a chemical reaction (redox reaction) to produce electricity or that uses electricity to product a chemical reaction.
2) Electrolysis: is the production of a chemical reaction using electricity.
3) Electroltic cell: is one of the two types of electrochemical cell. It is that in which electricity is used to produce the chemical reaction, i.e. where electrolysis happens. For example, the decomposition of sodium chloride brines is done in an electrolitic cell.
4) Galvanic cell: is the other type of electrochemical cell. It is that in which chemical reactions (redox reactions) produce electricity. The battery of the car is an example of a galvanic cell.
Here you are asked to identify which diagram shows a voltaic cell.So, you need to lool at:
- a redox reaction is happening
- this redox reaction is producing electricity (not that the electricity is producing the reaction)
Remember that a redox reaction is where some atoms are being reduced (gaining electros) and others are being oxidized (losing electrons).
Tha information will let you to choose the righ diagram.
Explanation:
The water is a polar solvent which means it strongly interact with the ionic species dissolved in it. The reason is due to the formation of Hydrogen bonding. Hence, the ionic species are known to be stabilized by solvation.
The H- bonding is the interaction of H-atom of solvent molecules with the electronegative atom of same molecule or, solute species. Ionic solutes dissolve by forming H- bonding.
But in case n- pentane which is a non polar and lack of H-atom attached to electronegative atom. Hence, there is no H- bonding.
Thus, the energy required to separate Na+ and Cl- ion would be huge in water compared to n-pentane.
Answer:
Tests for unsaturation involves addition across the multiple bonds in the unsaturated compound.
Explanation:
In organic chemistry, we define an unsaturated compound as any compound that contains a double or triple bond. These multiple bonds are also known as pi bonds.
There are two major tests for unsaturation which shall both be discussed here.
The first test for unsaturation is by the use of bromine water. The unknown sample is passed through a solution of bromine water which normally appears reddish brown. The bromine water becomes decolorized due to addition of bromine across the multiple bond. This is a standard test for unsaturation.
Secondly, unsaturated compounds decoulourize a solution of potassium permanganate when passed through it. This alone can not be used as a distinctive test for unsaturation.
Propenoic acid will give a positive test to the both reagents showing that it contains multiple bonds, in this particular instance, a double bond.
Make sure you numbers with variable are on one side and the numbers
