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Anit [1.1K]
3 years ago
15

Which formula represents an acid?

Chemistry
2 answers:
Veseljchak [2.6K]3 years ago
7 0
Are there answer choices or is this a write in answer?
Oduvanchick [21]3 years ago
6 0

what type of acid are you looking for?

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To how much water should 100 ml of 18m sulfuric acid be added to prepare a 1.5m solution
SashulF [63]

Answer:

Take 100 ml of a 18 molar solution. The total number of moles is (1 liter/1000 ml) 100 ml 18 moles is 1.8 moles.

1.5 moles in 1 liter so If 1.1 liters of water is added, the total volume is 1.2 liters and 1.8 moles are dissolves in it. 1.8 moles/ 1.2 liters is 1.5 moles per liter.

5 0
3 years ago
Matches=from Chemical energy to light energy+heat energy​
solong [7]

Explanation:

A matchstick has a lot of chemical energy stored in it. When the match is struck, it burns and the chemical energy in it produces heat energy and light energy.

brainliest and follow and thanks

7 0
3 years ago
It takes 90 N of force to lift a box of books off my smiths table. If you can only leave the box 25% of the way up, how many new
leva [86]

Answer:3.6 I think sorry if wrong

Explanation:

90 divided by 25

4 0
2 years ago
Find the number of moles in 3.62 x 1024 atoms of helium.
Makovka662 [10]
3.62x10^24/ 6.02x10^23=  6.013 moles to 3dp
8 0
3 years ago
Read 2 more answers
How many milliliters of 0.125 M FeCl3 are needed to react with an excess of Na2S to produce 3.75 g of Fe2S3 if the percent yield
Katyanochek1 [597]

Answer:

0.912 mL

Explanation:

3 Na2S(aq) + 2 FeCl3(aq) → Fe2S3(s) + 6 NaCl(aq)

FeCl3 is the limiting reactant.

Number of moles of iron III sulphide produced= 3.75g/87.92 g/mol = 0.043 moles

Hence actual yield of Iron III sulphide = 0.043 moles

Theoretical yield of Iron III sulphide = actual yield ×100%/ %yield

Theoretical yield of iron III sulphide= 0.043 ×100/75 = 0.057 moles of Iron III sulphide

From the reaction equation,

2moles of iron III chloride produced 1 mole of iron III sulphide

x moles of iron III chloride, will produce 0.057 of iron III sulphide

x= 2× 0.057= 0.114 moles of iron III chloride

But

Volume= number of moles/ concentration

Volume= 0.114/0.125

Volume= 0.912 mL

4 0
3 years ago
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