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dimaraw [331]
3 years ago
11

Jack said, five times my age 3 years ago equals 104. how old is jill now

Mathematics
1 answer:
rusak2 [61]3 years ago
4 0
The answer to this question is 107 3 plus 104 equals 107 <span />
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(20 points and brainlest to whoever answers correctly!!!)
Stells [14]

Answer:

y = -2/3x - 11

Step-by-step explanation:

Steps to find the perpendicular bisector:

1) Find the midpoint of line PQ

Midpoint formula: (\frac{x_{1} + x_{2} }{2} \\, \frac{y_{1} + y_{2}}{2})

Midpoint of line PQ = (6, -2)

2) Find the slope of line PQ

Slope formula: \frac{y_{2} - y_{1}}{x_{2} - x_{1}}

Slope of line PQ = 3/2

3) Find the negative reciprocal of the slope of PQ

To find the negative reciprocal just swap the numerator and denominator and add a negative sign. If it is already negative it will become positive.

In this case it will be -2/3

4) Write the equation of line PQ in slop-intercept form.

Slope-intercept form: y = mx + b

This is what it will look like for line PQ: y = \frac{3}{2}x + b

5) Plug the points of the midpoint into the line and solve for the intercept (b)

This is what it will look like: -2 = \frac{3}{2}(6) + b

-2 = 18/2 + b

-2 = 9 + b

-11 = b

6) Write the equation of the perpendicular bisector

m = the negative reciprocal of the slope of PQ = -2/3

This is what the equation will look like: y = -2/3x - 11

Hope this helped! Please give Brainliest!

5 0
3 years ago
Please please look at the picture and help me with this
kenny6666 [7]

Step-by-step explanation:

ur right because y is pumpkin 3 is the slope and x is the apple

6 0
1 year ago
Angle RST is a right angle. Angle RSU has a measure of 25°.
Angelina_Jolie [31]

Keywords

complementary angles, right angle

we know that

If two angles are <u>complementary angles</u>, then their sum is equal to a <u>right angle</u>

In this problem

Angle\ RSU+Angle\ TSU=90\° -------> by <u>complementary angles</u>

we have

Angle\ RSU=25\°

Substitute and solve for Angle TSU

Angle\ TSU=90\°-25\°=65\°

therefore

the answer is the option

65\°

5 0
3 years ago
Read 2 more answers
A room has an area of 60 square meters and a perimeter of 32 meters. What are the length and width of the room?
SOVA2 [1]
6 and 10 because 6 times 10 is 60 and 6 plus 6 plus 20 plus 10 is 32
4 0
3 years ago
Read 2 more answers
What is the mode and mean for class A and the range and medium for class B????
melamori03 [73]
Hello!

First you have to list the data in both classes

Class A
41, 42, 45, 46, 47, 48, 52, 53, 54, 59, 61, 61, 64, 68, 71, 82, 85, 90

Class B
41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95
------------------------------------------------------------------------------------------------------
First we are going to find the mode and mean of class A

The mode is the number that appears the most

The number that appears the most is 61

The mode is 61

To find the mean you add all the numbers together and divide the sum by the amount of numbers added

41 + 42 + 45 + 46 + 47 + 48 + 52 + 53 + 54 + 59 + 61 + 61 + 64 + 68 + 71 + 82 + 85 + 90 = 1069

Divide this by the amount of numbers added

1069 / 18 = 59.3888...

The mean is 59.3888

The mode is 61 and the mean is 59.39 for class A
------------------------------------------------------------------------------------------------------
We are going to find the range and median for class B

To find the range you subtract the smallest number from the largest on

The smallest number is 41
The largest number is 95

Subtract these

95 - 41 = 54

The range is 54

To find the median you list the numbers from least to greatest and look for the number in the middle

41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95

The number in the middle is 78

The range is 54 and the median is 78
------------------------------------------------------------------------------------------------------
Hope this helps!
6 0
3 years ago
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