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3 years ago

Jack said, five times my age 3 years ago equals 104. how old is jill now

Mathematics

1 answer:

rusak2 [61]3 years ago

4 0

The answer to this question is 107 3 plus 104 equals 107 <span />

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AB is a diameter of a circle, center O. C is a point on the circumference of the circle, such that

Solnce55 [7]

Given:

AB is the diameter of a circle.

m∠CAB = 26°

To find:

The measure of m∠CBA.

Solution:

Angle formed in the diameter of a circle is always 90°.

⇒ m∠ACB = 90°

In triangle ACB,

Sum of the angles in the triangle = 180°

m∠CAB + m∠ACB + m∠CBA = 180°

26° + 90° + m∠CBA = 180°

116° + m∠CBA = 180°

Subtract 116° from both sides.

116° + m∠CBA - 116° = 180° - 116°

m∠CBA = 64°

The measure of m∠CBA is 64°.

7 0

3 years ago

700=132.69x-25.96 <br> solve please

Damm [24]

Answer:

x = 5.5 (rounded)

Step-by-step explanation:

Equation: 700 = 132.69x - 25.96

Add 25.96 to both sides: 700+25.96 = 132.69x -25.96 + 25.96

Simplify: 725.96 = 132.69x

Isolate x

Divided both sides by 132.69: $\frac{725.96}{132.69} = \frac{132.69x}{132.69}$

Simplify: x = 5.5 (rounded)

7 0

3 years ago

Find the range of the function for the given domain: f(x)=2x^2−7 with domain: x = {-4, -2, 0, 3}

-BARSIC- [3]

Answer:

f(x)=2(-4)^2-7

=-8^2-7

= 64-7

=57

7 0

3 years ago

1-2m-5m=15 multistep homework

Montano1993 [528]

1-2m-5m=15

combine like terms

1 -7m = 15

subtract 1 from each side

1-1-7m = 15-1

simplify

-7m = 14

divide by -7

-7m/-7 = 14/-7

simplify

m = -2

6 0

3 years ago

Which radical expression in the picture is equivalent to t^5/8?

mixas84 [53]

<h3>Answer: Choice B</h3>

=========================================================

Explanation:

The rule we use is

$\Large a^{m/n} = \sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m$

where 'a' is the base, m stays in the role of the exponent, and n plays the role of the root index (eg: n = 3 is a cube root, n = 4 is a fourth root, and so on).

So for instance,

$\Large 2^{3/4} = \sqrt[4]{2^3} = \left(\sqrt[4]{2}\right)^3$

or in this case,

$\Large t^{5/8} = \sqrt[8]{t^5} = \left(\sqrt[8]{t}\right)^5$

5 0

3 years ago