The combustion of ethane is expressed in the balanced reaction C2H6 + 3.5O2= 2CO2 + 3 H2O. Given the mass of oxygen gas, we get the moles of ethane needed by converting this mass to mole (dividing my 32 g/mol), then multiply by 1/3.5 (stioch ratio) and the molar mass of ethane (30 g/mol). The answer is 16.69 grams ethane.
Depending on the balloon, the surface will cause friction between the two and oxygen molecules will fuse together to create a sticky sensation
Answer:
1/ Using the first letter of the name of the elements.
2/ If the name of two or more elements begins with the same letter,the second letter of their name is also taken with first letter.
3/ Symbols are made by using the letters of the name of elements in other languages also.
Answer:
Explanation:
Molecular weight of 
= 100.0869 g/mol
Mass of = 31.7 g
Moles of = 
Moles of both 
and 
is 
Molecular weight of = 44 g/mol
Mass of = 
The mass of carbon dioxide formed simultaneously is .
