All categories

3 years ago

The molar mass of aniline is 93 g/mol. what is its molecular formula

Chemistry

1 answer:

Mashutka [201]3 years ago

4 0

Answer:

Molecular formula of aniline is C6H5NH2.

Explanation:

As we know, molecular mass can be calculated as

Molar mass = C6H5NH2

Molar mass = (6*12)+(1*7)+(28)

Molar mass = 93 g/mol

You might be interested in

Aluminum reacts with sulfur gas to produce aluminum sulfide

weqwewe [10]

Answer:

What is the question? It looks like a fact.

Explanation:

4 0

3 years ago

A sound wave moves from a solid material into a liquid. What would happen to the frequency of the sound?

Mariana [72]

The frequency of the sound waves travel faster and more effectively in liquids than in air and travel even more effectively in solids.

7 0

3 years ago

Oxygen, nitrogen, and carbon are all _____. metalloids nonmetals metals halogens

Radda [10]

They're all nonmetals

7 0

3 years ago

Read 2 more answers

"The sun was setting behind the mountain when Isaiah reached the first fields of crops, bordered by low white stone walls. At th

kvasek [131]

░░░░░▐▀█▀▌░░░░▀█▄░░░

░░░░░▐█▄█▌░░░░░░▀█▄░░

░░░░░░▀▄▀░░░▄▄▄▄▄▀▀░░

░░░░▄▄▄██▀▀▀▀░░░░░░░

░░░█▀▄▄▄█░▀▀░░

░░░▌░▄▄▄▐▌▀▀▀░░

▄░▐░░░▄▄░█░▀▀ ░░

▀█▌░░░▄░▀█▀░▀ ░░

░░░░░░░▄▄▐▌▄▄░░░

░░░░░░░▀███▀█░▄░

░░░░░░▐▌▀▄▀▄▀▐▄░░

░░░░░░▐▀░░░░░░▐▌░░

░░░░░░█░░░░░░░░█░

This is bob. If you brainliest him. He will reward you with a certain script.

5 0

3 years ago

12oz of water initially at 75oF is mixed with 20oz of water intiially at 140oF. What is the final temperature?

Kaylis [27]

Answer:

$115.625^{\circ}\text{F}$

Explanation:

$m_1$ = First mass of water = 12 oz

$m_2$ = Second mass of water = 20 oz

$\Delta T_1$ = Temperature difference of the solution with respect to the first mass of water = $(T-75)^{\circ}\text{F}$

$\Delta T_2$ = Temperature difference of the solution with respect to the second mass of water = $(T-75)^{\circ}\text{F}$

c = Specific heat of water

As heat gain and loss in the system is equal we have

$m_1c\Delta T_1=m_2c\Delta T_2\\\Rightarrow m_1\Delta T_1=m_2\Delta T_2\\\Rightarrow 12(T-75)=20(140-T)\\\Rightarrow 12T-900=2800-20T\\\Rightarrow 12T+20T=2800+900\\\Rightarrow 32T=3700\\\Rightarrow T=\dfrac{3700}{32}\\\Rightarrow T=115.625^{\circ}\text{F}$

The final temperature of the solution is $115.625^{\circ}\text{F}$ .

3 0

3 years ago