Answer:
The bulk modulus of the liquid is 1.229 x 10¹⁰ Pa
Explanation:
Given;
density of liquid, ρ = 1400 kg/m³
frequency of the wave, f = 390 Hz
wavelength, λ = 7.60 m
The speed of the sound is given by;
v = fλ
v = 390 x 7.6
v = 2964 m/s
The bulk modulus of the liquid is given by;
where;
B is bulk modulus
B = (1400)(2964)²
B = 1.229 x 10¹⁰ N/m²
B = 1.229 x 10¹⁰ Pa
Therefore, the bulk modulus of the liquid is 1.229 x 10¹⁰ Pa
Answer:
Centrifugal force
Explanation:
In Space, It is in a way possible create an " artificial gravity" just by spinning the aircraft or space station. On spinning the space station the inhabitants feel an outward force or the centrifugal force, this outward force when equivalent to gravitational force is able to stimulate gravity.
Answer:
When the object is placed between centre of curvature and principal focus of a concave mirror the image formed is beyond C as shown in the figure and it is real, inverted and magnified.
Answer:
Equation of motion
Explanation:
this equation is known as the second equation of motion and it is used to calculate the distance travelled (s) by a body in time (t), the body having initial velocity (u) and acceleration (a). This equation has four values in it, so if any three values are known, the fourth value can be calculated.
There are two equations to be used for this problem. The firs one is the general formula for heat transfer:
Q = kAΔT
where
Q is the rate of heat transfer
k is the heat transfer coefficient
A is the cross-sectional area
ΔT is the temperature difference
Substituting the values:
Q = (454 W/m²·K)(4.6x10⁻⁴ m²)(871°C - 482°C)
Q = 81.24 W
Thus, the rate of heat transfer is 81.24 W.
We use the Q for the second equation. The radial heat transfer would be:
Q = 2πkL(T₁ - T₂)/ ln (r₂/r₁)
where
L is the length of the turbine
r₂ is the distance of tip blade to the center
r₁ is the distance of root blade to the center
T₂ is temperature at the tip blade
T₁ is temperature at the root blade
Perimeter = 2πr₂
0.12 m = 2πr₂
r₂ = 0.019 m
Cross-sectional area = πr₁²
4.6x10⁻⁴ m² = πr₁²
r₁ = 0.012 m
Substituting to the equation:
81.24 W = 2π(454 W/m²·K)(6.3 cm * 1m/100 cm)(482°C - T₂)/ln (0.019 m/0.012 m)
Solving for T₂,
T₂ = 481.79°C