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3 years ago

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In your daily life you come across a range of motion in which acceleration is in the direction of motion

1 answer:

irakobra [83]3 years ago

3 0

That makes no sense to me somehow

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The downward acceleration of a falling body on Earth is 9.81m/s2. On the moon the same quantity is 1.62m/s2. An astronaut in a s

Bas_tet [7]

The astronaut's mass doesn't change. It's the same wherever he goes,
because it doesn't depend on what else is around him.

His weight depends on what else is near him, so it changes, depending
on where he is.

   Weight = (mass) x (gravity)

On Earth, Weight = (145 kg) x (9.81 m/s²) = 1,422.5 newtons.
   (about 320 pounds)

On the moon, Weight = (145 kg) x (1.62 m/s²) = 234.9 newtons.
   (about 53 pounds)

5 0

3 years ago

A 15.4 kg block is dragged over a rough, horizontal surface by a constant force of 182 N acting at an angle of 24◦ above the hor

Dima020 [189]

Answer:

Explanation:

Considering Work done by friction is asked

Given

mass of block $m=15.4\ kg$

force $F=182\ N$

inclination $\theta =24^{\circ}$

block is displaced by $s=57.6\ m$

coefficient of kinetic friction $\mu _k=0.135$

Friction force $F_r=\mu _kN$

Normal reaction $N=mg-F\sin \theta =15.4\times 9.8-182\sin (24)$

$N=76.9\ N$

Friction Force $F_r=0.135\times 76.9=10.38\ N$

Work done by friction force

$W=f_r\cdot s$

$W=10.38\times 57.6=597.92\ N$

3 0

3 years ago

Each tire on a car has a radius of 0.330 m and is rotating with an angular speed of 11.7 revolutions/s. Find the linear speed v

Eduardwww [97]

Answer:

The linear speed of the car, v, is 24.26 m/s

Explanation:

Given;

radius of the car's tire, r = 0.330 m

angular speed of the car, ω = 11.7 revolutions/s

The angular speed of the car in radian per second:

$\omega = 11.7 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} \\\\\omega = 73.523 \ rad/s$

The linear speed of the car, v, is calculated as;

v = ωr

v = 73.523 rad/s x 0.33 m

v = 24.26 m/s

Therefore, the linear speed of the car, v, is 24.26 m/s

7 0

3 years ago

One who voluntarily donates tissues/ organs striped

Artist 52 [7]

A tissue donor is what you're probably looking for. :)

8 0

3 years ago

In diving to a depth of 248 m, an elephant seal also moves 296 m due east of his starting point. What is the magnitude of the se

Vinvika [58]

Answer:

The displacement is 386.16m

Explanation:

A seal dives to a depth of 248m. To find displacement, we must calculate the resultant vectors which will give us the displacement

R= sqrt(vector1+vector2)

Since this is a right angle triangle

R= sqrt(248^2 + 296^2)

R= sqrt(149120)

R= 386.16m

Displacement = 386.16m

4 0

3 years ago