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mariarad [96]
3 years ago
11

In your daily life you come across a range of motion in which acceleration is in the direction of motion

Physics
1 answer:
irakobra [83]3 years ago
3 0
That makes no sense to me somehow
You might be interested in
You walk 20 meters north, then 5 meters south. what is your displacement?
Svetllana [295]
The answer is C. 15 meters North

Displacement is the distance and direction from the origin. If you move 20 meters North, your displacement is 20 meters North. If you move 5 meters South, you are basically moving back the way you came by 5 meters, which means you are now 15 meters North.

I hope this helped! :)

3 0
3 years ago
A person can run 280 m in 68 s. At what speed are they running?
ella [17]

Answer:

Explanation:

Hi there,

280 miles in 68 seconds

280/68 in 1 second

= 4.12 miles per second

 

or 4.12 x 60

247.2 miles per minute

or 247.2 X 60

= 14832 miles per hour

Hope this helps :-)

6 0
3 years ago
Read 2 more answers
The medium through which a mechanical wave passes can be a solid, liquid, or gas. Properties of a wave change when it moves from
Tpy6a [65]

Answer:

Option A

Explanation:

Mechanical waves requires some medium to travel through. They travel faster in the dense medium as compared to a free medium.

The speed of a mechanical wave is fastest in the solid medium and the slowest in the gaseous medium. Hence, as the wave traverses from gaseous medium to the solid medium, its speed increases.

Thus, option A is correct

3 0
3 years ago
1. The current in a wire is 0.72A. Calculate the charge that passes through the wire in; a. 4 s b. 60 s c. 180 s d. 7 s e. 0.5 s
Vlad [161]
Let current be I, charge be Q and time be t.
Here we are provided with,
I = 0.72A
t = 4s / 60s / 180s / 7s / 0.5s
We know,
I = Q/t

Case I
---------
When, t = 4s
0.72 = Q/4
Q = 0.72 * 4 = 2.88C

Case II
----------
When, t = 60s
0.72 = Q/60
Q = 0.72 * 60 = 43.2C

Case III
-----------
When, t = 180s
0.72 = Q/180
Q = 0.72 * 180 = 129.6C

Case IV
-----------
When, t = 7s
0.72 = Q/7
Q = 0.72 * 7 = 5.04C

Case V
----------
When, t = 0.5s
0.72 = Q/0.5
Q = 0.72 * 0.5 = 0.36C
6 0
3 years ago
A 5 cm spring is suspended with a mass of 3.8589 g attached to it which extends the spring by 1.5747 cm. The same spring is plac
lana66690 [7]

Answer:

charges of the beads is 1.173 ×10^{-15} C

Explanation:

given data

mass = 3.8589 g = 0.003859 kg

spring length = 5 cm = 0.05 m

extend spring x = 1.5747 cm = 0.15747 m

spring's extension = 0.0116 m

to find out

charges of the beads

solution

we know that force is

force = mass × g

force = 0.003859 × 9.8

force = 0.03782 N

so we know  force for mass

force  = -kx

so k = force / x

put here force and x value

k = -0.03782 / 0.1575

k = -0.24 N/m

and

force for spring's extension

force = -kx

force = -0.24 ( 0.0116) = 0.002784 N

so here

total length L = 0.05 + 0.0116 = 0.0616

so charges of the beads = force × L² / ke

charges of the beads = 0.002784 × (0.0616)² / (9 ×10^{9} )

so charges of the beads = 1.173 ×10^{-15} C

3 0
3 years ago
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