A man travels 15 km east before turning around and heading 5 km west. What is his displacement?
2 answers:
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Answer:
a. V=11.84 m/s
b.x=0.052m
Explanation:
a).
Given
,
,
.
b).
No friction on the ball so:
Answer:
The distance covered by puck A before collision is
Explanation:
From the question we are told that
The label on the two hockey pucks is A and B
The distance between the two hockey pucks is D 18.0 m
The speed of puck A is
The speed of puck B is
The distance covered by puck A is mathematically represented as
=>
The distance covered by puck B is mathematically represented as
=>
Since the time take before collision is the same
substituting values
=>
=>
The sum of the series allows to find the result for the total distance that the ball bounces is:
total distance = 59.52 in
A series is a set of things or numbers related by a specific operation.
They indicate that the ball falls from an initial height y₀ = 30 in. and it bounces 50% of the height and the process is repeated until it stops, see attached.
Let's build a table to observe the sequence.
drop height rebound
1 30 15
2 15 7.5
3 7.5 3.75
If we call the first term y₀
The first bounce can be found.
y₁ =
The second bounces.
The third bounce.
By observing this table we can construct a series of the form
Total distance =
The sum of the serie has a result of
sum = 127/64 = 1,984
Let's calculate
distance total = 30 1,984
Distance total = 59.52 cm
In conclusion, using the sum of the series we can find the result for the total distance that the ball bounces is:
total distance = 59.52 in
Learn more here: brainly.com/question/8879163
