Answer:
A for 1 and 4 B for 2 and 3 ..........
Answer:
behavior of objects for which all existing forces are not balanced.
Explanation:
1. So 27.3 g Fe is 0.4911 mol (27.3 / 55.58). 45.8 g O is 2.862 mol. Because of the stoichiometry, 3/4 as much oxygen as iron gets consumed. For the 0.4911 mol Fe consumed, 0.3683 mol O is consumed. 2.862-0.3863 = 2.4757 mol, or 39.6 g O is left.
2. Hydrogen is the limiting reactant for these quantities. 2/3 as much ammonia is produced as hydrogen is consumed, so for 5.0 mol H2, that's 3.33 mol NH3.
Make sense?
Answer:
Kf = [[Hg(NH₃)₄]²⁺] / [Hg²⁺] [NH₃]⁴
Last step: [Hg(NH₃)₃]²⁺ + NH₃(aq) ⇄ [Hg(NH₃)₄]²⁺(aq)
Explanation:
When the Hg²⁺ ion is in presence of ammonia molecules in an aqueous solution, the tetrahydrated complex is formed, following the equilibriums:
Hg²⁺(aq) + NH₃(aq) ⇄ [Hg(NH₃)]²⁺(aq) K₁
[Hg(NH₃)]²⁺ + NH₃(aq) ⇄ [Hg(NH₃)₂]²⁺(aq) K₂
[Hg(NH₃)₂]²⁺ + NH₃(aq) ⇄ [Hg(NH₃)₃]²⁺(aq) K₃
<em>[Hg(NH₃)₃]²⁺ + NH₃(aq) ⇄ [Hg(NH₃)₄]²⁺(aq) </em> K₄ → Last step.
Global reaction is:
Hg²⁺(aq) + 4 NH₃(aq) ⇄ [Hg(NH₃)₄]²⁺(aq)
And Kf is defined as:
<em>Kf = [[Hg(NH₃)₄]²⁺] / [Hg²⁺] [NH₃]⁴</em>
2nd one bhutdsaadxjytwwdghurfc