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Airida [17]
2 years ago
10

a chemical company claims that they are able to produce a certain product thermodynamically unfavored process. Explain how this

is possible
Chemistry
1 answer:
KonstantinChe [14]2 years ago
8 0
Thermodynamically favored process are those processes that do not require any assistance from outside the system e.g water boils at 25 degrees. Thermodynamically unfavored processes require assistance from outside to induce the required change for example water doesn't freeze at 15 degrees and therefore for that to happen several factors in the system have to be modified to achieve this. Therefore, there is a possibility of companies to produce product by using thermodynamically unfavored process by inducing changes in the system to achieve desired change or modification.
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Which of the following is a nonrenewable resource?
dybincka [34]

C. Natural gas

Hope this helps!

8 0
3 years ago
Read 2 more answers
Menthol, the substance we can smell in mentholated cough drops, is composed of C, H, and O. A 0.1005 g sample of menthol is comb
Bogdan [553]

<u>Answer:</u> The molecular formula for the menthol is C_{10}H_{20}O

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=0.2829g

Mass of H_2O=0.1159g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

  • <u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 0.2829 g of carbon dioxide, \frac{12}{44}\times 0.2829=0.077g of carbon will be contained.

  • <u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 0.1159 g of water, \frac{2}{18}\times 0.1159=0.0129g of hydrogen will be contained.

  • Mass of oxygen in the compound = (0.1005) - (0.077 + 0.0129) = 0.0106 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon = \frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.077g}{12g/mole}=0.0064moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.0129g}{1g/mole}=0.0129moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.0106g}{16g/mole}=0.00066moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00066 moles.

For Carbon = \frac{0.0064}{0.00066}=9.69\approx 10

For Hydrogen  = \frac{0.0129}{0.00064}=19.54\approx 20

For Oxygen  = \frac{0.00066}{0.00066}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 10 : 20 : 1

Hence, the empirical formula for the given compound is C_{10}H_{20}O_1=C_{10}H_{20}O

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

We are given:

Mass of molecular formula = 156.27 g/mol

Mass of empirical formula = 156 g/mol

Putting values in above equation, we get:

n=\frac{156.27g/mol}{156g/mol}=1

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(1\times 10)}H_{(1\times 20)}O_{(1\times 1)}=C_{10}H_{20}O

Thus, the molecular formula for the menthol is C_{10}H_{20}O

4 0
2 years ago
Read 2 more answers
4. A galvanic cell is formed when two metals are immersed in solu- tions differing in concentration 1 when two different metals
emmasim [6.3K]

A galvanic cell is formed when two metals are immersed in solutions differing in concentration 1 when two different metals are immersed.

<h3>What is galvanic cell?</h3>

A galvanic cell is an electrochemical device that transforms chemically generated free energy into electrical energy. A photogalvanic cell produces photochemical species that react to produce an electrical current when connected to an external circuit.

<h3>How does galvanic cell works?</h3>

In order to create a pathway for the flow of electrons via this wire, the galvanic cell makes use of the ability to split the flow of electrons during the processes of oxidation and reduction, forcing a half-reaction and linking each with a wire.

An electrochemical device known as a galvanic cell converts chemical energy from a spontaneous redox response into electrical energy. It possesses an electrical potential of 1.1 V. The anode, which is a negative plate in galvanic cells, is where oxidation takes place. It is a positive plate where lessening takes place.

To learn more about galvanic cell visit:

brainly.com/question/13031093

#SPJ4

8 0
1 year ago
an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem
OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

P\cdot V = n\cdot R\cdot T,

\displaystyle V = \frac{n\cdot R\cdot T}{P}.

where

  • P is the pressure of the gas,
  • V is the volume of the gas,
  • n is the number of moles of particles in this gas,
  • R is the ideal gas constant, and
  • T is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of R will be 8.314 if P, V, and T are in SI units. Convert these values to SI units:

  • P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa;
  • V shall be in cubic meters, \rm m^{3};
  • T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K.

Apply the ideal gas law:

\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}.

4 0
3 years ago
Describe how lead sulfate can be prepared using silver hydroxide​
Anastaziya [24]

Answer:

i would have to add and divide

Explanation:

adding and dividing will get you the answer

4 0
2 years ago
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