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3 years ago

You should always engage the parking brake whenever using any type of lift.

Engineering

1 answer:

Shtirlitz [24]3 years ago

8 0

Answer:

I would yes every time so it would not role off the lift

Explanation:

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Choose the statement that correctly describes the circuit below. image is not found a. The above circuit is invalid because nMOS

OleMash [197]

The statement that correctly describes the circuit is the circuit provided is an example of a CMOS circuit.

<h3>What is a CMOS circuit?</h3>

The CMOS circuit is a term that is often known as "Complementary Metal Oxide Semiconductor."

This is known to be a machine that create integrated circuits and it is one that is often seen a a lot of electronic component and as such, the the circuit provided is an example of a CMOS circuit.

Learn more about circuit from

brainly.com/question/2969220

#SPJ1

8 0

2 years ago

An undeformed specimen of some alloy has an average grain diameter of 0.050 mm. You are asked to reduce its average grain diamet

aleksandrvk [35]

Answer:

Yes it is possible

Explanation:

Procedures to be taken:

Step 1:

I will deform the specimen, that is, I will subject the specimen to plastic deformation at room temperature.

Step 2:

Also, I will anneal the deformed specimen at a high temperature.

Step 3:

Then, recrystallize the annealed specimen

Step 4:

Finally, I will facilitate the grain growth until the average grain diameter becomes 0.02mm.

5 0

3 years ago

3. (a) (5 points) Suppose N packets arrive simultaneously to a link at which no packets are currently being transmitted or queue

Bezzdna [24]

Answer:

(N-1) × (L/2R) = (N-1)/2

Explanation:

let L is length of packet

R is rate

N is number of packets

then

first packet arrived with 0 delay

Second packet arrived at = L/R

Third packet arrived at = 2L/R

Nth packet arrived at = (n-1)L/R

Total queuing delay = L/R + 2L/R + ... + (n - 1)L/R = L(n - 1)/2R

Now

L / R = (1000) / (10^6 ) s = 1 ms

L/2R = 0.5 ms

average queuing delay for N packets = (N-1) * (L/2R) = (N-1)/2

the average queuing delay of a packet = 0 ( put N=1)

4 0

4 years ago

Q.14

Kay [80]

Answer:

A. optical isolation

Explanation:

well I can't really give a good explanation because I also saw the same question in my exams and option A was the correct answer

6 0

3 years ago

Problem 9.11 A structural component in the form of a wide plate is to be fabricated from a steel alloy that has a plane strain f

BabaBlast [244]

Answer:

the critical flaw length is 10.06 mm

Explanation:

Given the data in the question;

plane strain fracture toughness $K_{tc$ = 92 Mpa√m

yield strength σ $_y$ = 900 Mpa

design stress is one-half of the yield strength ( 900 Mpa / 2 ) 450 Mpa

Y = 1.15

we know that;

Critical crack length $a_c$ = 1/π( $K_{tc$ / Yσ )²

we substitute

$a_c$ = 1/π( 92 Mpa√m / (1.15 × 450 Mpa )²

$a_c$ = 1/π( 92 Mpa√m / (517.5 Mpa )²

$a_c$ = 1/π( 0.177777 )²

$a_c$ = 1/π( 0.03160466 )

$a_c$ = 0.01006 m = 10.06 mm

Therefore, the critical flaw length is 10.06 mm

{ $a_c$ = ( 10.06 mm ) > 3 mm

The critical flow is subject to detection

5 0

3 years ago