Answer:
And Im still going with B..
The hypothesis that would help restore equilibrium is reintroduce wolves in the park or into the forest.
<h3>What is reintroduce?</h3>
To reintroduce, is a term that means to revive, reinstate, or bring back something.
Note that based on the right recommendation needed by National Park Service, one can say that the best hypothesis that would help restore equilibrium is reintroduce wolves in the park or into the forest as it will help restore balance.
Learn more about hypothesis from
brainly.com/question/24149728
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Pretty sure it’s Cenozoic
Answer:
Iin(t) =1.3 × (-0.8/1.56) e^-t/1.56 A
Explanation:
In physics, the determination of the term " natural response" simply means that we want to know what happens in a circuit when the value of t = 0, that is to say after the circuit has been disconnected. Hence, the value of the voltage and the current can then be determined or Calculated;
For the the natural response of i in(t) we will be using the formula below;
I(t) = Vo × t/ R = Vo/R × e^-t/h.
Where h = 1/RC = time constant.
For t= 0^- = 0.8 × 1= 0.8 V.
1/Ctotal = 1/ 2 + 1/3 = 6/5
For t = 0^+;
h =( 0.8 + 0.5) × 6/5 = 1.56 seconds.
Hence, we will have;
Vin(t) = 0.8 × e^-t/1.56.
Iin(t) =1.3 × (-0.8/1.56) e^-t/1.56
Answer:
Explanation:
Given data:
Ammonia Nitrogen 30 mg/L
pH = 8.5
-log[H +] = 8.5
[H +] = 10^{-8.5}
Rate constant is given as
![K_a = \frac{[H^{+}] [NH_3]}{NH_4^{+}}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%20%5BNH_3%5D%7D%7BNH_4%5E%7B%2B%7D%7D)
...........1
Total ammonia as NItrogen is given as 30 mg/l
![\%NH_4^{+} = \frac{ [NH_4] \times 100}{[NH_4^{+}] + [NH_3]}](https://tex.z-dn.net/?f=%5C%25NH_4%5E%7B%2B%7D%20%3D%20%5Cfrac%7B%20%5BNH_4%5D%20%5Ctimes%20100%7D%7B%5BNH_4%5E%7B%2B%7D%5D%20%2B%20%5BNH_3%5D%7D)
= 
.....2
from equation 1 we have
![\frac{NH_3^+}{NH_4^+} =\frac{K_a}{[H^+]} = \frac{5.6\times 10^{-10}}](https://tex.z-dn.net/?f=%5Cfrac%7BNH_3%5E%2B%7D%7BNH_4%5E%2B%7D%20%3D%5Cfrac%7BK_a%7D%7B%5BH%5E%2B%5D%7D%20%3D%20%5Cfrac%7B5.6%5Ctimes%2010%5E%7B-10%7D%7D)
{10^{8.5}}
plug this value in equation 2 we get
Total ammonia as N = 30 mg/lt
