Ask question

Ask question

All categories

alexandr402 [8]

3 years ago

9

1.50μm2. Convert this to square meters.

1 answer:

mars1129 [50]3 years ago

6 0

Based on the standards of units conversion, to convert from micrometer to meter, we multiply by 10^-6.
Since we there is a square (10^2) to consider, then to convert from micrometer squared to meter squared, we will multiply by (10^-6)^2 as follows:
1.5 <span>μm2 = 1.5 x (10^-6)^2 = 1.5 x 10^-12 meter sqaures</span>

You might be interested in

Hydrogen sulfide burns form sulfur dioxide:

Helga [31]

Answer: 404.04 kJ.

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

moles of $H_2S$

$\text{Number of moles}=\frac{26.7g}{34.1g/mol}=0.78moles$

$2H_2S(g)+3O_2(g)\rightarrow 2SO_2(g)+2H_2O(g)$ $\Delta H=-1036kJ$

According to stoichiometry :

2 moles of $H_2S$ on burning produces = 1036 kJ

Thus 0.78 moles of $H_2S$ on burning produces = $\frac{1036kJ}{2}\times 0.78=404.04$

Thus the enthalpy change when burning 26.7 g of hydrogen sulfide is 404.04 kJ.

7 0

3 years ago

Many different localities are thought to be hotspots, found overlying mantle plumes, although scientists cannot agree on a defin

borishaifa [10]

(If this is correct, can I have Brainlist?)

Answer:

D) anomalous volcanoes such as those in Hawaii

4 0

2 years ago

Calculate the mass percent composition of carbon in C4F8

Anon25 [30]

My work to your question

4 0

3 years ago

At 500 K the reaction 2 NO(g) + Cl2(g) ⇌ 2 NOCl(g) has Kp = 51 In an equilibrium mixture at 500 K, the partial pressure of NO is

Aleks [24]

Answer:

p3=0.36atm (partial pressure of NOCl)

Explanation:

2 NO(g) + Cl2(g) ⇌ 2 NOCl(g) Kp = 51

lets assume the partial pressure of NO,Cl2 , and NOCl at eequilibrium are P1 , P2,and P3 respectively

$Kp=\frac{[NOCl]^{2} }{[NO]^{2} [Cl_2] }$

$Kp=\frac{[p3]^{2} }{[p1]^{2} [p2] }$

p1=0.125atm;

p2=0.165atm;

p3=?

Kp=51;

On solving;

p3=0.36atm (partial pressure of NOCl)

7 0

3 years ago

When combining acids and water, water should always be added to the acid. True or False?

scoundrel [369]

Answer:

False

Explanation:

Always add acid to the water, it dilutes the acid the other way around.

8 0

2 years ago