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zvonat [6]
3 years ago
7

Problem 1 The Van de Graaff electrostatic generator develops a charge of approximately −1 × 10−5C and a pith ball has charge of

approximately 1 × 10−9C. Which of the following describes the relationship between the size of the force the Van de Graaff exerts on the pith ball and the size of the force the pith ball exerts on the Van de Graaff? Select One of the Following: (a) The Van de Graaff exerts a much larger force on the pith ball. (b) The pith ball exerts a much larger force on the Van de Graaff. (c) The forces have the same magnitude.
Physics
1 answer:
Ilya [14]3 years ago
8 0

Answer:

(c) The forces have the same magnitude.

Explanation:

The electric Force between the two charges are proportional to the product of both charges:

F_{electric}=k*q_{1}q_{2}/r^{2}

Both charges feels the same force but with opposite direction.

(c) The forces have the same magnitude.

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In a standard tensile test a steel rod of 22-mm diameter is subjected to a tension force of 75kN. Knowing that v = 0.30 and E =
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Answer:

(a) Elongation of rod = 0.19732 mm

(b) Change in diameter = 0.00651 mm

Explanation:

Circular area at end of steel rod = pi * diameter^2 / 4

Area = pi * (22 * 10^-^3)/4

Area = 3.801 * 10^(-4)    meter squared

Stress = force / area

Stress = 75000 / (3.801 * 10^-4)

Stress = 197316495 Pa     OR       0.197 GPa

Modulus of elasticity = stress / strain

200 = 0.19732 / Strain

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(a) Strain = change in length / initial length

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(b) Poisson ratio = lateral strain / longitudinal strain

0.3 = lateral strain / 0.0009866

Lateral strain = 0.000296

Lateral strain = Change in diameter / original diameter

0.000296 = Change in diameter / 22

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