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telo118 [61]
3 years ago
12

Joel has a mass of 50kg he is spending his firs day on skis. His friend is trying to push him across a level patch of snow. Joel

friend is pushing with 60N of force but Joel does not move why?
Physics
1 answer:
insens350 [35]3 years ago
3 0

Joel does not move because the frictional force acting on him is also 60 N

Explanation:

The force of static friction is a force that acts on objects at rest, in the direction opposite to the force that is trying to put the object in motion.

The value of the force of static friction goes from zero to a maximum value given by

F_f = \mu_s mg

where

\mu_s is the coefficient of static friction

m is the mass of the object

g is the acceleration of gravity

In order to move the object, the force which is pushing it must overcome this maximujm value of the force of friction, otherwise the force of friction will balance the pushing object preventing the object to move.

In this problem, there are two forces acting on Joel:

- The pushing force, F=60 N, forward

- The frictional force, F_f, backward

According to Newton's second law of motion,

F-F_f = ma

where a is the acceleration of Joel. However, Joel is at rest, so the acceleration is zero:

a=0\\F-F_f = 0 \rightarrow F_f = F

which means that the frictional force is equal to the pushing force of 60 N, preventing Joel from moving.

Learn more about force of friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

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The change in potential energy is  \Delta  PE =  -  3.8*10^{-16} \ J

Explanation:

From the question we are told that

     The  magnitude of the uniform electric field  is  E =  950 \ N/C

      The  distance traveled by the electron is  x =  2.50 \ m

Generally the force on this electron is  mathematically represented as

     F =  qE

Where F is the force and  q is the charge on the electron which is  a constant value of  q =  1.60*10^{-19} \ C

    Thus  

      F  =  950  * 1.60 **10^{-19}

      F  = 1.52 *10^{-16} \ N

Generally the work energy theorem can be mathematically represented as

          W =  \Delta  KE

Where W is the workdone on the electron by the  Electric field and  \Delta  KE  is the change in kinetic energy

Also  workdone on the electron can also  be represented as

        W =  F* x  *cos(  \theta )

Where  \theta  =  0 ^o considering that the movement of the electron is along the x-axis  

        So

             \Delta  KE  =  F  * x  cos  (0)

substituting values

         \Delta  KE  =  1.52 *10^{-16}  * 2.50   cos  (0)

          \Delta  KE   =  3.8*10^{-16} J

Now From the law of energy conservation

       \Delta PE  =  -  \Delta  KE

Where \Delta  PE is the change  in  potential energy  

Thus  

        \Delta  PE =  -  3.8*10^{-16} \ J

               

7 0
3 years ago
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