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BlackZzzverrR [31]
3 years ago
5

Which of the following is a harmful effect of oil spills? (A)Migration of large schools of fish (B)Changes in sea level (C)Plant

photosynthesis decreases (D)Increased ocean pH
Physics
2 answers:
Anarel [89]3 years ago
6 0

Answer: C) Plant photosynthesis decreases

Explanation: An oil spill may impact on various ways, it can be harmful to plants and animals, change the ph of the water (which also affects the wildlife in the water), dangerous emissions, and one thing you need t to have in mind is that these effects may last from 2 to 5 or more years.

Then the two options that made sense are options C and D.

The change in the Ph made by the oil spills is the opposite of the showed in option D, the Ph decreases, which made the water more acidic, so we can discard the option D.

And we end up with option C, plant photosynthesis decrease, this is because the thicker oil blocks the sunlight to the plants underwater, and then there is less sunlight received by them, which affects their photosynthesis.

kotegsom [21]3 years ago
4 0
C is your answer to the question
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A satellite in a circular orbit of radius R around planet X has an orbital period T. If Planet X had one-fourth as much mass, th
Iteru [2.4K]
<h2>Answer: 2T</h2>

According to the Third Kepler’s Law of Planetary motion <em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.</em>

In other words, this law states a relation between the orbital period T of a body (moon, planet, satellite) orbiting a greater body in space with the size R of its orbit.

This Law is originally expressed as follows (in the case of planet X and assuming we have a circular orbit):

T^{2}=\frac{4\pi^{2}}{GM}R^{3}    (1)

Where:

G is the Gravitational Constant

M=1.9(10)^{27}kg is the mass of planet X

R  is the radius of the orbit of the satellite around planet X

If we want to find the period, we have to express equation (1) as written below and substitute all the values:

T=2\pi\sqrt{\frac{R^{3}}{GM}}   (2)

Now, we are asked to find the period when tha mass of the planet is \frac{1}{4}M. In order to do this, we have to rewrite equation (2) with this new value:

T=2\pi\sqrt{\frac{R^{3}}{G(\frac{1}{4}M)}}  (3)

Solving:

T=4\pi\sqrt{\frac{R^{3}}{G(\frac{1}{4}M)}}   (4)

On the other hand, if we multiply both sides of equation (2) by 2, we have:

2T=4\pi\sqrt{\frac{R^{3}}{GM}}    (5)

As we can see, (5) is equal to (4). This means the orbital period is twice the orignal period.

Hence, the answer is:

If Planet X had <u>one-fourth </u>as much mass, the <u>orbital period</u> of this satellite in an orbit of the same radius would be <u>2T.</u>

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Two speakers, one directly behind the other, are each generating a 280-Hz sound wave. What is the smallest separation distance b
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Answer:

1.21m

Explanation:

If two speakers are generating a frequency of 280Hz, the smallest separation distance between the speakers that will produce destructive interference at a listener standing in front of them is also known as the wavelength of the sound wave generated.

Using the expression;

Velocity v = frequency f × wavelength ¶

Given frequency = 280Hz, speed of sound v = 338m/s

Substituting this data's in the expression given to get the wavelength will give;

¶ = v/f

¶ = 338/280

¶ = 1.21m

The smallest separation between the speakers that will produce the interference is 1.21m

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Answer:

you want to know newtons first law here.

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An object that is at rest stays at rest or stays in motion.

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