Answer:
I'm pretty sure its 3m/s^2 for the acceleration but I don't know the force part sorry .
Explanation:
15m/s - 0m/s divided by 5 s = 3m/s
I'm no expert or anything so I could be wrong but this is the best I can give you. Sorry
The potential across the capacitor at t = 1.0 seconds, 5.0 seconds, 20.0 seconds respectively is mathematically given as
- t=0.476v
- t=1.967v
- V2=4.323v
<h3>What is the potential across the capacitor?</h3>
Question Parameters:
A 1. 0 μf capacitor is being charged by a 9. 0 v battery through a 10 mω resistor.
at
- t = 1.0 seconds
- 5.0 seconds
- 20.0 seconds.
Generally, the equation for the Voltage is mathematically given as
v(t)=Vmax=(i-e^{-t/t})
Therefore
For t=1
V=5(i-e^{-1/10})
t=0.476v
For t=5s
V2=5(i-e^{-5/10})
t=1.967
For t=20s
V2=5(i-e^{-20/10})
V2=4.323v
Therefore, the values of voltages at the various times are
- t=0.476v
- t=1.967v
- V2=4.323v
Read more about Voltage
brainly.com/question/14883923
Complete Question
A 1.0 μF capacitor is being charged by a 5.0 V battery through a 10 MΩ resistor.
Determine the potential across the capacitor when t = 1.0 seconds, 5.0 seconds, 20.0 seconds.
Answer:
V = 42.41cm^3
Explanation:
In order to calculate the volume of the solid, you use the following formula:
where
r: radius of the circular base of the cone = 3 cm
h: height from the circular base to the peak of the cone = 4.5 cm
You replace the values of r and h in the formula for the volume V:
hence, the volume of the solid is 42.41 cm^3
