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Schach [20]
3 years ago
6

________ skids occur when the brakes are applied so hard that the front or rear wheels lost traction. Cornering

Physics
2 answers:
pochemuha3 years ago
8 0

Answer:

Braking skid

Explanation:

When you apply brake very hard so that the rear wheel lost traction leads to the occurrence of Braking skid.

Skid occurs when the Tyre looses it grip from the road due to sudden brake or road being smooth and many more reasons.

Skid can be due to the worn off Tyre.

some time skidding can cause accident also so  one should use good Tyre for their vehicle.

mihalych1998 [28]3 years ago
7 0

Answer:

Braking skid

Explanation:

A skid occurs when a vehicle is moving on the road and the tires of the vehicle lose their hold on the roadway.

Braking skid occurs when the brakes are applied suddenly and the braking is very hard that it results in the lose of hold of the rear wheels and the rear wheels lose grasp over the road resulting in the skid of the vehicle.

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Which of the following best expresses the definition of mass?
sergey [27]
The quantity of matter in a body regardless of its volume or of any forces acting on it.
4 0
3 years ago
A 91.5 kg football player running east at 2.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft
vivado [14]

Their velocity afterwards is 2.88 m/s east

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, for an isolated system (= no external force), the total momentum must be conserved before and after the collision. So we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1 + m_2)v

where: in this case:

m_1 = 91.5 kg is the mass of the first player

u_1 = 2.73 m/s is the initial velocity of the first player (choosing east as positive direction)

m_2 = 63.5 kg is the mass of the second player

u_2 = 3.09 m/s is the initial velocity of the second player

v is their combined velocity afterwards

Solving for v, we find:

v = \frac{m_1 u_1+m_2 u_2}{m_1+m_2}=\frac{(91.5)(2.73)+(63.5)(3.09)}{91.5+63.5}=2.88 m/s

And the sign is positive, so the direction is east.

Learn more about momentum here:

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7 0
3 years ago
If a 100 N net force acts on a 50 kg car, what will the acceleration of the car will be?
Allushta [10]
According to newton's law Force = mass * acceleration
so , 100 = 50 * a
so , a= 2 m/s^2
6 0
3 years ago
6. An aircraft is is travelling along a runway at a Velocity of 25m/s in It accelerates at a rate of 4m/s² for a distance of 750
zysi [14]

Answer:

Take-off velocity = v = 81.39[m/s]

Explanation:

We can calculate the takeoff speed easily, using the following kinematic equation.

v_{f}^{2}=v_{i}^{2} +2*a*x

where:

a = acceleration = 4[m/s^2]

x = distance = 750[m]

vi = initial velocity = 25 [m/s]

vf = final velocity

v_{f}=\sqrt{(25)^{2}+(2*4*750) } \\v_{f}=81.39[m/s]

7 0
3 years ago
What are some forces that come in pairs?
Nikolay [14]

Answer:

ACTION REACTION FORCES

Explanation:

When there is an action frce there will be a reaction force

3 0
3 years ago
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