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3 years ago

________ skids occur when the brakes are applied so hard that the front or rear wheels lost traction. Cornering

Physics

2 answers:

pochemuha3 years ago

8 0

Answer:

Braking skid

Explanation:

When you apply brake very hard so that the rear wheel lost traction leads to the occurrence of Braking skid.

Skid occurs when the Tyre looses it grip from the road due to sudden brake or road being smooth and many more reasons.

Skid can be due to the worn off Tyre.

some time skidding can cause accident also so one should use good Tyre for their vehicle.

mihalych1998 [28]3 years ago

7 0

Answer:

Braking skid

Explanation:

A skid occurs when a vehicle is moving on the road and the tires of the vehicle lose their hold on the roadway.

Braking skid occurs when the brakes are applied suddenly and the braking is very hard that it results in the lose of hold of the rear wheels and the rear wheels lose grasp over the road resulting in the skid of the vehicle.

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Which word describes a goal that is poorly written?

stiv31 [10]

Abstract. Abstract is defined as an idea or plan but no actions are done

to pursue the idea. When setting goals, one must be certain and it should be attainable in order

to achieve the goal being set. Goals that are abstract

are often poorly written and uncertain

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3 years ago

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When running your engine, you cause debris, rocks and propeller blast to be directed towards people or other aircraft. Is this c

beks73 [17]

Answer:

Yes, it is reckless. This is because it is the responsibility of the pilot to make sure that the direction of the propeller blast is away from people or other aircraft and in a safe direction.

Explanation:

Yes, it is reckless to let the propeller blast face people and other aircraft. This is because it is the responsibility of the pilot to make sure that the direction of the propeller blast is away from people or other aircraft and in a safe direction. People and other aircraft can be injured by the debris and the rocks that are scattered by the engine of the aircraft.

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3 years ago

A 3-kg rock is thrown upward with a force of 200 N at a location where the local gravitational acceleration is 9.79 m/s2 . Deter

expeople1 [14]

Answer: $56.87m/s^{2}$

Explanation:

If we make an analysis of the net force $F_{net}$ of the rock that was thrown upwards, we will have the following:

$F_{net}=F_{up}-W$ (1)

Where:

$F_{up}=200N$ is the force with which the rock was thrown

$W$ is the weight of the rock

Being the weight the relation between the mass $m=3kg$ of the rock and the acceleration due gravity $g=9.79m/s^{2}$ :

$W=m.g=(3kg)(9.79m/s^{2})$ (2)

$W=29.37 N$ (3)

Substituting (3) in (1):

$F_{net}=200N-29.37 N$ (4)

$F_{net}=170.63 N$ (5) This is the net Force on the rock

On the other hand, we know this force is equal to the multiplication of the mass with the acceleration, according to Newton's 2nd Law:

$F_{net}=m.a$ (6)

Finding the acceleration $a$ :

$a=\frac{F_{net}}{m}$ (7)

$a=\frac{170.63 N}{3kg}$ (8)

Finally:

$a=56.87m/s^{2}$

3 0

3 years ago

Calculate the critical angle for light going from Glycerine to air.

Georgia [21]

The refractive index for glycerine is $n_g=1.473$ , while for air it is $n_a = 1.00$ .

When the light travels from a medium with greater refractive index to a medium with lower refractive index, there is a critical angle over which there is no refraction, but all the light is reflected. This critical angle is given by:
$\theta_c = \arcsin ( \frac{n_2}{n_1} )$
where n1 and n2 are the refractive indices of the two mediums. If we susbtitute the refractive index of glycerine and air in the formula, we find the critical angle for this case:
$\theta_c = \arcsin ( \frac{1.00}{1.473} )=42.8^{\circ}$

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3 years ago

The intensity of a sound wave at a fixed distance from a speaker vibrating at 1.00 kHz is 0.600 W/m2.

LenKa [72]

Answer:

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