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Kamila [148]
3 years ago
7

Which of the following statements is true?

Chemistry
2 answers:
Ivan3 years ago
5 0

Answer:

B.

Explanation:

Most metals can be drawn into a wire while nonmetals would break apart.

natima [27]3 years ago
4 0

Answer:

Most metals can be drawn into a wire, while nonmetals would break apart.

Explanation:

Most of the metals can be drawn into wire without breaking because their tensile strength is high. This property of metals is known as ductility.

Non metals on the other hand do not have this ability because they are brittle and tend to break apart because their tensile strength is very low.

The examples of metals which are generally used for making wires are aluminium, iron, copper etc. and rarely gold and silver are used for making wires for expensive equipments like computers.

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I'm having trouble with my wireless headphones that won't turn on at all it's not blinking why? need help asap.....​
svetoff [14.1K]

Answer:

Try a hard reset: Press and hold both the power button and the volume button (plus the other 2 as well perhaps) for about 10 seconds and then release. Check if the earphones will then either show that they are charging (with the cable inserted of course) or that they will turn on if the Power button is pressed.                                                                                                                          Explanation:Hope this helped you

8 0
3 years ago
In a Lewis structure for carbon tetrachloride (CCl4), which of the following is the central atom?
Sonbull [250]
Carbon is the answer it is the main molecule in the atom
3 0
3 years ago
After the child exhaled all of the gas, it becomes sick
tensa zangetsu [6.8K]
What is your question about it?
5 0
2 years ago
Read 2 more answers
PLEASE HELP
swat32

Answer:

1461.7 g of AgI

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI

Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:

Mole of AgI = 6.22 moles

Molar mass of AgI = 108 + 127

= 235 g/mol

Mass of AgI =?

Mass = mole × molar mass

Mass of AgI = 6.22 × 235

Mass of AgI = 1461.7 g

Therefore, 1461.7 g of AgI were obtained from the reaction.

5 0
3 years ago
Balance the following half reaction in basic conditions. Then, indicate the coefficients for H2O and OH– for the balanced half r
Ugo [173]

Answer:

The ballance half reactions are:

Mg²⁺  + 2e⁻ → Mg

6OH⁻ + Si  → SiO₃²⁻ + 4e⁻ + 3 H₂O

Coefficients for H2O and OH– are 3 for H₂O (in products side) and 6 for OH⁻ (in reactants side)

Explanation:

Si (s) + Mg(OH)₂ (s) → Mg (s) + SiO₃²⁻ (aq)

Let's see the oxidations number.

As any element in ground state, we know that oxidation state is 0, so Si in reactants and Mg in products, have 0.

Mg in reactants, acts with +2, so the oxidation number has decreased.

This is the reduction, so it has gained electrons.

Si in reactants acts with 0 so in products we find it with +4. The oxidation number increased it, so this is oxidation. The element has lost electrons.

Let's take a look to half reactions:

Mg²⁺  + 2e⁻ → Mg

Si  → SiO₃²⁻ + 4e⁻

In basic medium, we have to add water, as the same amount of oxygen we have, IN THE SAME SIDE. We have 3 oxygens in products, so we add 3 H₂O and in the opposite site we can add OH⁻, to balance the hydrogen. The half reaciton will be:

6OH⁻ + Si  → SiO₃²⁻ + 4e⁻ + 3 H₂O

If we want to ballance the main reaction we have to multiply (x2) the half reaction of oxidation. So the electrons can be ballanced.

2Mg²⁺  + 4e⁻ → 2Mg

Now, that they are ballanced we can sum the half reactions:

2Mg²⁺  + 4e⁻ → 2Mg

6OH⁻ + Si  → SiO₃²⁻ + 4e⁻ + 3 H₂O

2Mg²⁺  + 4e⁻  + 6OH⁻ + Si  → 2Mg  +  SiO₃²⁻ + 4e⁻ + 3 H₂O

7 0
3 years ago
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