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3 years ago

How does the structure of the alveoli relate to its function in the lungs

Physics

1 answer:

slavikrds [6]3 years ago

8 0

Structure of Alveoli provides more surface area for lungs, to exchange the gases & for process of respiration

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The position of a particle is given by ~r(t) = (3.0 t2 ˆi + 5.0 ˆj j 6.0 t kˆ) m

Julli [10]

Answer:

$v=(6ti+6k)\ m/s$

Explanation:

Given that,

The position of a particle is given by :

$r(t) = (3.0 t^2 i + 5.0j+ 6.0 tk) m$

Let us assume we need to find its velocity.

We know that,

$v=\dfrac{dr}{dt}\\\\=\dfrac{d}{dt}(3.0 t^2 i + 5.0j+ 6.0 tk) \\\\=(6ti+6k)\ m/s$

So, the velocity of the particle is $(6ti+6k)\ m/s$ .

5 0

2 years ago

A 1500 kg car is parked at the top of a hill 5.2 m high. At the bottom of the hill, what is the kinetic energy, in Joules, of th

irga5000 [103]

Answer:

10.1

Explanation:

I think it's right?

4 0

2 years ago

1. Why is it important to use units in any graph?

Scorpion4ik [409]

Answer:

so its easier to understand for the reader

Explanation:

4 0

3 years ago

Read 2 more answers

A trombone can produce pitches ranging from 85 Hz to 660 Hz approximately. When the trombone is producing a 562 Hz tone, what is

tester [92]

To solve this problem we will apply the concept of wavelength, which warns that this is equivalent to the relationship between the speed of the air (in this case in through the air) and the frequency of that wave. The air is in standard conditions so we have the relation,

Frequency $= f = 562Hz$

Speed of sound in air $= v = 331m/s$

The definition of wavelength is,

$\lambda = \frac{v}{f}$

Here,

v = Velocity

f = Frequency

Replacing,

$\lambda = \frac{331m/s}{562Hz}$

$\lambda = 0.589m$

Therefore the wavelength of that tone in air at standard conditions is 0.589m

3 0

3 years ago

If an object went from 0 m/s to 6 m/s in 1.7 seconds after a 10 N force was applied to it; what is the object's mass? No links p

Mashcka [7]

The force acting on the object is constant, so the acceleration of the object is also constant. By definition of average acceleration, this acceleration was

a = ∆v / ∆t = (6 m/s - 0) / (1.7 s) ≈ 3.52941 m/s²

By Newton's second law, the magnitude of the force F is proportional to the acceleration a according to

F = m a

where m is the object's mass. Solving for m gives

m = F / a = (10 N) / (3.52941 m/s²) ≈ 2.8 kg

4 0

2 years ago