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4 years ago

14

How does the structure of the alveoli relate to its function in the lungs

1 answer:

slavikrds [6]4 years ago

8 0

Structure of Alveoli provides more surface area for lungs, to exchange the gases & for process of respiration

You might be interested in

When a weather map shows a wind symbol at 270 it indicates that the wind is coming from the?

Montano1993 [528]

For the answer to the question above, <span>When a weather map shows a wind symbol at 270 it indicates that the wind is coming from the WEST.
I hope my answer helped you. Feel free to ask more questions. Have a nice day!</span>

5 0

3 years ago

The light turns green and a stationary racing car accelerates at 7.815 m/s/s. How much time does it take the car to reach a velo

Alexeev081 [22]

Assuming the acceleration stays constant, we have

$a=\dfrac{v-v_0}{t-t_0}$

where $v$ is the velocity of the car at time $t$ , $v_0=0$ is the starting velocity, and $t_0=0$ is the starting time. So

$a=\dfrac vt\iff7.815\,\dfrac{\mathrm m}{\mathrm s^2}=\dfrac{37.0\,\frac{\mathrm m}{\mathrm s}}t\implies t=\dfrac{37.0\,\frac{\mathrm m}{\mathrm s}}{7.815\,\frac{\mathrm m}{\mathrm s^2}}$

$\implies t\approx4.73\mathrm s$

8 0

3 years ago

During a high-speed car chase, a gangster's car flies off of a cliff. If it takes 7.15 seconds for the car to reach the ground b

Ksju [112]

Answer:

255.61 m

Explanation:

Use $s=ut +\frac{1}{2} at^{2}$ in downwards direction from the moment of flight till the car hits the bottom.

As the car fly off the cliff the velocity of the car in vertical direction will be zero.

$h =\frac{1}{2} 10(7.15)^{2}$

$h=255.61 m$

7 0

4 years ago

Cyclist A is moving at 20.0 m/s whereas cyclist B is moving at 12.0 m/s in the same direction and is initially ahead ofA. When t

stealth61 [152]

Answer:

$v_{fA} = 28 \frac{m}{s}$

Explanation:

The kinematic parameters from the moment the two cyclists begin to accelerate until they meet are:

Initial parameters:

$v_{oA} = 20 m/s$ : Initial speed of cyclist A

$v_{oB} = 12 m/s$ : Initial speed of cyclist B

Final parameters:

$v_{fB} = 20 m/s$ : Final speed of cyclist B

$d_{A} = d_{B}$

distance of cyclist A = distance of cyclist B

$t_{A} =t_{B} = 12s$

time of cyclist A = time of cyclist B

Cyclist B Kinematics

$v_{fB} = v_{oB} +a_{B} *t\\$

$36= 12 + a_{B} *12$

$a_{B} = \frac{36-12}{12}$

$a_{B} = 2 \frac{m}{s^{2} }$

$d_{B} =( v_{oB})*( t)+( \frac{1}{2} )*(a_{B})* (t)^{2}$

$d_{B} =( 12*(12)+( \frac{1}{2} )*(2)* (144)}$

$d_{B} = 288m$

Cyclist A Kinematics

$d_{A} =( v_{oA})*( t)+( \frac{1}{2} )*(a_{A})* (t)^{2}$

$d_{A} =(20*( 12)+( \frac{1}{2} )*(a_{A})* 144}$

$d_{A} = 240 + 72*(a_{A})$

$288=240+72*(a_{A} )$

$a_{A} = \frac{288-240}{72}$

$a_{A} = 0.67 \frac{m}{s^{2} }$

$v_{fA} = v_{oA} + a_{A} * t$

$v_{fA} = 20 + 0.67*12$

$v_{fA} = 28 \frac{m}{s}$

7 0

3 years ago

What term is a force that can slow momentum <br><br> A. mass<br><br> B. friction

jenyasd209 [6]

Your answer is friction. Friction between to object slows the object down.

3 0

3 years ago

Read 2 more answers