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Mila [183]
3 years ago
6

A stone is thrown vertically upward with a speed of 18.0 m/s. How fast is it moving when it reaches a height of 11.0m? How long

does it take to reach the height?
Physics
1 answer:
steposvetlana [31]3 years ago
8 0
Given: v0= 18.0 m/s, y0=0m, yf=11m, g=-9.81 m/s^2 

v0= initial velocity, vf= final velocity, y0= initial height, yf= final height, g= gravity, sqrt()= square root, ^2=squared 

vf^2=v0^2 + (2)(g)(yf-y0) 
vf^2=(18.0 m/s)^2+(2)(-9.81 m/s^2)(11 m-0m) 
vf^2=18.0 m/s)^2 + (-19.62 m/s^2)(11 m)
vf^2=(324 m^2/s^2) - (215.82 m^2/s^2) 
vf^2=108.18 m^2/s^2 
vf=sqrt(108.18 m^2/s^2) 
vf=10.4 m/s
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The atmospheric pressure on a mountain is 550 mmHg and 1 atm is equal to 760 mmHg. What is the pressure in atm? Give your answer
Svetradugi [14.3K]

Answer:

0.72 atm

Explanation:

Given that the atmospheric pressure on a mountain is 550 mmHg.

Where 1 atm is equal to 760 mmHg.

To Convert millimetre mercury (mmHg) into atmospheric pressure units (atm) , divide the magnitude of pressure by 760. That is,

Pressure = 550/760

Pressure = 0.724 atm

Therefore, pressure in atm is 0.72 atm in two significant figures

4 0
3 years ago
A uniform disk of mass 3.25 kg has a radius of 0.100 m and spins with a frequency of 0.550 rev/s. What is its angular momentum?
shutvik [7]

ANSWER:

0.0562 J

STEP-BY-STEP EXPLANATION:

Angular momentum is expressed in terms of moment of inertia and angular velocity. This is expressed as follows:

L=I\cdot\omega

Here, I is the angular momentum and ω is the angular velocity.

Angular momentum is mass time the square of the radius of the object. Moment of inertia for a uniform disk is given as,

I=\frac{1}{2}m\cdot r^2

Here, m is the mass of the disk and r is the radius of the disk.

Replacing:

L=\frac{1}{2}m\cdot r^2\cdot\omega

Convert the units of angular velocity into rad/s.

\begin{gathered} \omega=0.55\text{ rev/s}\cdot\frac{2\pi\text{ rad}}{1\text{ rev}} \\ \omega=3.46\text{ rad/s} \end{gathered}

We replace each data to calculate the angular momentum:

\begin{gathered} L=\frac{1}{2}\cdot3.25\cdot0.1^2\cdot3.46 \\ L=0.0562 \end{gathered}

The angular momentum of the uniform disk is 0.0562 J

7 0
1 year ago
During a baseball game, a batter hits a popup to a fielder 83 m away. The acceleration of gravity is 9.8 m/s 2 . If the ball rem
topjm [15]

Answer:

41.2 m.

Explanation:

It takes half the time that is (5.8/2) = 2.9 seconds, for the ball to reach its apex.

Given:

S = 83 m

t = 5.8 s

vf = 0 m/s

a = - g

= - 9.81 m/s^2

Equations of motion:

i. vf = vi + a * t

ii. h = vi * t + 1/2 (a * t²)

Using the i. equation of motion:

0 m/s = vi - (9.8 m/s²) (2.9 sec)

vi = 28.4 m/s.

Using the ii. equation of motion:

h = (28.4 * 2.9 ) - 1/2 (9.8 * (2.9)²)

= 82.4 - 41.2

= 41.2 m.

3 0
3 years ago
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