A stone is thrown vertically upward with a speed of 18.0 m/s. How fast is it moving when it reaches a height of 11.0m? How long
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Answer:
The time taken for the paint ball to hit the ground is
The distance of the landing point from the tower is
Explanation:
From the question we are told that
The height of the tower is
The speed of the paintball in the horizontal direction is
Generally from kinematic equation we have that
Here u is the initial velocity of the paintball in the vertical direction and the value is 0 m/s , this because the ball was fired horizontally
a is equivalent to
t is the time taken for the paintball to hit the ground
So
=>
Generally the distance of its landing position from the tower is
=>
=>
Explanation:
It is given that,
Length of the rod, l = 14 cm = 0.14 m
Charge on the rod,
We need to find the magnitude and direction of the net electric field produced by the charged rod at a point 36.0 cm to the right of its center along the axis of the rod, z = 36 cm = 0.36 m
Electric field at the axis of the rod is given by :
Where
is the linear charge density of the rod,
E = -7493170.57 N/C
or
Negative sign shows that the electric field is acting in inwards direction. Hence, this is the required solution.