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2 years ago

Which statements accurately describe the shape of Earth’s orbit around the Sun? Check all that apply.

2 answers:

4 0

The Earth’s orbit is a nearly circular ellipse.
The Sun is located at one of the two focal points.

The Earth moves around the Sun in an orbit that is almost but not quite circular. As Kepler proved in the seventeenth century, the orbit is actually an ellipse. A parameter called the eccentricity (e) defines the degree of departure from a circle. A value of e=0 would indicate a circle whereas a value of e=0.9 would indicate a very elongated ellipse. The eccentricity of the Earth's orbit is currently e=0.0167.

anyanavicka [17]2 years ago

4 0

2. The Earth’s orbit is a nearly circular ellipse.

5. The Sun is located at one of the two focal points.

These are the two correct answers.

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Block A of mass M is on a horizontal surface of negligible friction. An identical block B is attached to block A by a light stri

miv72 [106K]

Answer:

T’= 4/3 T

The new tension is 4/3 = 1.33 of the previous tension the answer e

Explanation:

For this problem let's use Newton's second law applied to each body

Body A

X axis

T = m_A a

Axis y

N- W_A = 0

Body B

Vertical axis

W_B - T = m_B a

In the reference system we have selected the direction to the right as positive, therefore the downward movement is also positive. The acceleration of the two bodies must be the same so that the rope cannot tension

We write the equations

T = m_A a

W_B –T = M_B a

We solve this system of equations

m_B g = (m_A + m_B) a

a = m_B / (m_A + m_B) g

In this initial case

m_A = M

m_B = M

a = M / (1 + 1) M g

a = ½ g

Let's find the tension

T = m_A a

T = M ½ g

T = ½ M g

Now we change the mass of the second block

m_B = 2M

a = 2M / (1 + 2) M g

a = 2/3 g

We seek tension for this case

T’= m_A a

T’= M 2/3 g

Let's look for the relationship between the tensions of the two cases

T’/ T = 2/3 M g / (½ M g)

T’/ T = 4/3

T’= 4/3 T

The new tension is 4/3 = 1.33 of the previous tension the answer e

4 0

2 years ago

Strike441 [17]

Answer:

it have to be a

Explanation:

3 0

2 years ago

Without friction, what force is needed to maintain a 1,000 kg car in uniform motion for 30 minutes?

VARVARA [1.3K]

The answer is none. According to the first law of Newton, an object stays at the same speed in the same direction if there are not forces unbalancing the object. Without friction, the car would be moving forever, unless there is another force accelerating or stopping the car.

6 0

3 years ago

Quinn accelerates her skateboard along a straight path from 0 m/s to 4.0 m/s in 2.5 seconds. Calculate the acceleration of the s

Sedaia [141]

Answer: 16 m/s^2

Explanation:

Vf = Vi + at

40 = 0 + 2.5a

a = 40 / 2.5 = 16 m/s^2

7 0

2 years ago

Read 2 more answers

In addition to plate tectonics, what is the other main driving force of the rock cycle?

GREYUIT [131]

Answer: Option B

Explanation:

Rocks contains pores and spaces in them in which water gets trapped, and this causes the rock to break as water increases its volume due to freezing. This rocks are then eroded and are carried away into the streams and channels. The rivers and streams can carry particles of various shapes and size, which are further transported and deposited at a different place.

This particles or sediments then gets compacted and lithified in due course of time, and forms sedimentary rocks.

Water is also needed to undergo metasomatism process, that creates a metamorphic rock.

Hence, water flow is also an important driving force in rock cycle, along with tectonic activities.

Thus, the correct answer is option (B).

4 0

2 years ago

Read 2 more answers