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Zanzabum
3 years ago
8

Which statements accurately describe the shape of Earth’s orbit around the Sun? Check all that apply.

Physics
2 answers:
damaskus [11]3 years ago
4 0
<span>The Earth’s orbit is a nearly circular ellipse.
</span><span>The Sun is located at one of the two focal points.</span>

The Earth moves around the Sun in an orbit that is almost but not quite circular. As Kepler proved in the seventeenth century, the orbit is actually an ellipse. A parameter called the eccentricity (e) defines the degree of departure from a circle. A value of e=0 would indicate a circle whereas a value of e=0.9 would indicate a very elongated ellipse. The eccentricity of the Earth's orbit is currently e=0.0167.
anyanavicka [17]3 years ago
4 0

2. The Earth’s orbit is a nearly circular ellipse.

5. The Sun is located at one of the two focal points.

These are the two correct answers.

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Help? I don't know how to do this.
aliya0001 [1]

Use the definition of acceleration:

Acceleration = (change of velocity) divided by (time for the change)

The graph says:

Change of velocity = -6 m/s

Time for the change = 3 sec

So Acceleration = (-6m/s) / (3 s)

That's -6/3 m/s•s

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-2 m/s^2

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4 years ago
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denis23 [38]
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3 years ago
as earth rotates about it’s axis, it takes three hours for the united states to pass beneath a point above earth that is station
pickupchik [31]

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6 0
3 years ago
Charge g is distributed in a spherically symmetric ball of radius a. (a) Evaluate the average volume charge density p. (b) Now a
nasty-shy [4]

Answer:

Explanation:

The volume of a sphere is:

V = 4/3 * π * a^3

The volume charge density would then be:

p = Q/V

p = 3*Q/(4 * π * a^3)

If the charge density depends on the radius:

p = f(r) = k * r

I integrate the charge density in spherical coordinates. The charge density integrated in the whole volume is equal to total charge.

Q = \int\limits^{2*\pi}_0\int\limits^\pi_0  \int\limits^r_0 {k * r} \, dr * r*d\theta* r*d\phi

Q = k *\int\limits^{2*\pi}_0\int\limits^\pi_0  \int\limits^r_0 {r^3} \, dr * d\theta* d\phi

Q = k *\int\limits^{2*\pi}_0\int\limits^\pi_0 {\frac{r^4}{4}} \, d\theta* d\phi

Q = k *\int\limits^{2*\pi}_0 {\frac{\pi r^4}{4}} \,  d\phi

Q = \frac{\pi^2 r^4}{2}}

Since p = k*r

Q = p*π^2*r^3 / 2

Then:

p(r) = 2*Q / (π^2*r^3)

3 0
3 years ago
Which of the following best describes the term thermal energy? Choose one: A. The energy of an object in motion due to its mass
o-na [289]

Answer:

The correct option is (d).

Explanation:

  • The energy a particle has because of its charge and its position relative to another particle is called thermal energy.
  • It is the energy that comes from heat. This is generated by the movement of the particles in an object.
  • Thermal energy is the energy an object or system has due to the movement of particles within.

Hence, the correct option is (d).

8 0
3 years ago
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