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3 years ago

8

Which statements accurately describe the shape of Earth’s orbit around the Sun? Check all that apply.

2 answers:

damaskus [11]3 years ago

4 0

<span>The Earth’s orbit is a nearly circular ellipse.
</span><span>The Sun is located at one of the two focal points.</span>

The Earth moves around the Sun in an orbit that is almost but not quite circular. As Kepler proved in the seventeenth century, the orbit is actually an ellipse. A parameter called the eccentricity (e) defines the degree of departure from a circle. A value of e=0 would indicate a circle whereas a value of e=0.9 would indicate a very elongated ellipse. The eccentricity of the Earth's orbit is currently e=0.0167.

anyanavicka [17]3 years ago

4 0

2. The Earth’s orbit is a nearly circular ellipse.

5. The Sun is located at one of the two focal points.

These are the two correct answers.

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Lilit [14]

Answer:

6m/s^2

Explanation:

at=Vf-Vi

a=? a(5)=65-35

t=5 a(5)=30

Vi=35 a(5)/5=30/5

Vf=65 a=6m/s^2

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3 years ago

Which word identifies a large natural or human-made lake used to supply water?

Sidana [21]

Reservoir i think. i’m not sure

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3 years ago

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What type of electromagnetic waves is released by all objects?

Juli2301 [7.4K]

Answer:

a)Visibile light waves

Explanation:

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3 years ago

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Logs sometimes float vertically in a lake because one end has become water-logged and denser than the other. What is the average

Elina [12.6K]

Answer: the average density (in kg/m3) of the log is 400 kg/m³

Explanation:

Given that;

a log with uniform-diameter floats with 60.0% of its length above water.

from the Archimedes principle formula;

friction submerged = Average density of object / density of fluid. --- equ 1

We know that; density of water = 1000 kg/m³

now the log floats with 60.0% of its length above water

so submerged fraction is 100% - 60% = 40% = 0.40

from our equation;

friction submerged = Average density of object / density of fluid

we substitute

0.40 = Average density of object / 1000 kg/m³

Average density of object = 0.40 × 1000

Average density of object = 400 kg/m³

Therefore; the average density (in kg/m3) of the log is 400 kg/m³

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3 years ago

A charged particle is injected at 211 m/s into a 0.0633‑T uniform magnetic magnetic field perpendicularly to the field. The diam

lakkis [162]

Answer:

$85.68*10^3C/kg$

Explanation:

For this problem we need the concept about Force in a Magnetic field,

For definition we know that

$F=m\frac{v^2}{r}$

Where v is the velocity, m the mass and r the radius or distance between the two points.

We know as well that

$F = qvB$

where q is the charge of a proton

v the velocity and B the magnetic field, then matching the two equation,

$qvB=m\frac{v^2}{r}$

Re-arrange for q/m (charge to mass ratio)

$\frac{q}{m} = \frac{v}{Br}$

Our values are,

$v=211m/s$

$B= 0.0633T$

$r=0.0389m$

Substituting,

$\frac{q}{m} = \frac{211}{0.0633*0.0389}$

$\frac{q}{m} = 85689.8 C/kg = 85.68*10^3C/kg$

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3 years ago