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bulgar [2K]
3 years ago
5

Given the two points (-1, 6) and (3, -2), write an equation in point-slope form.

Mathematics
2 answers:
abruzzese [7]3 years ago
8 0

Answer:

y-6 = -2(x+1)

Step-by-step explanation:

First we need to find the slope

m = (y2-y1)/(x2-x1)

   = (-2-6)/(3--1)

    = (-2-6)/(3+1)

     = -8/4

    = -2

Then we can point slope form where

y -y1 = m(x-x1)

where m is the slope and x1,y1 is a point

y-6 = -2(x--1)

y-6 = -2(x+1)

Zinaida [17]3 years ago
8 0

Answer:

y - 6 = -2(x + 1)

Step-by-step explanation:

Slope: (-2-6)/(3--1)

= -8/4

= -2

y - 6 = -2(x - -1)

y - 6 = -2(x + 1)

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56

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6 X 8 = 48

7 X 8 = 56

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A freight train is traveling at an average rate of 45 miles per hour. Which equation represents the situation? Let h represent t
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which inequality is represented by this graph? A. y<- 1/5x + 1 B. y< - 1/5 x + 1 C. y> - 1/5x + 1 D. y> -1/5 x +1
Molodets [167]

The inequality represented by the graph is y < -\frac 15x + 1

<h3>How to determine the inequality?</h3>

The attached image represents the missing piece of the question

From the graph, we can see that the inequality is represented by dotted lines and the down region is shaded.

This is represented using the less than sign.

So, the inequality is calculated using:

y < \frac{y_2 -y_1}{x_2 -x_1} * (x -x_1) + y_1

Where:

(x1, y1) = (0, 1) and (x2, y2) = (5,0)

So, we have:

y < \frac{0 -1}{5-0} * (x -0) + 1

Evaluate

y < -\frac 15x + 1

Hence, the inequality represented by the graph is y < -\frac 15x + 1

Read more about inequality at:

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5 0
2 years ago
TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streamin
choli [55]

Answer:

a) The 99% confidence interval would be given (0.523;0.577).

We are 99% confident that this interval contains the true population proportion.

b) n=\frac{0.55(1-0.55)}{(\frac{0.03}{2.58})^2}=1830.51  

And rounded up we have that n=1831

Step-by-step explanation:

Data given and notation  

n=2341 represent the random sample taken    

X represent the people that they have watched digitally streamed TV programming on some type of device

\hat p=0.55 estimated proportion of people that they have watched digitally streamed TV programming on some type of device  

\alpha=0.01 represent the significance level

Confidence =0.99 or 99%

z would represent the statistic for the confidence interval  

p= population proportion of people that they have watched digitally streamed TV programming on some type of device

The population proportion present the following distribution:

p \sim N (p, \sqrt{\frac{p(1-p)}{n}}

Part a) Confidence interval

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.55 - 2.58 \sqrt{\frac{0.55(1-0.55)}{2341}}=0.523

0.55 + 2.58 \sqrt{\frac{0.55(1-0.55)}{2341}}=0.577

And the 99% confidence interval would be given (0.523;0.577).

We are 99% confident that this interval contains the true population proportion.

Part b) What sample size would be required for the width of a 99% CI to be at most 0.03 irrespective of the value of p??

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.55(1-0.55)}{(\frac{0.03}{2.58})^2}=1830.51  

And rounded up we have that n=1831

8 0
4 years ago
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