Assuming that the initial pH is pHi.
The initial concentration of [OH-] is
[OH]- = 10^(14 - pHi)
Since half of the Na2HPO4 is neutralized, the concentration of [OH-] will be reduced to half. The new pH will be
[OH-]/2 = 10^(14 - pHi)/2 = 10^(14 - pH)
14 - pHi - log 2 = 14 - pH
In terms of pHi,
pH = pHi + log 2
Copper mass = 1.659
Copper moles = 1.659 / 64 = 0.0259
Sulfur mass = 2.08 - 1.659 = 0.421
Sulfur moles = 0.421 / 32 = 0.0131
Ratio Copper : Sulfur = 2 : 1
Empirical formula: Cu ₂ S
Name: Copper (I) sulfide
Answer:
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Explanation:
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Answer:
during reaction magnesium lises ions.
Explanation:
magnesium reacts by losing two ions which makes it smaller in size.
