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Deffense [45]
3 years ago
10

The acceleration due to gravity near Earth ... Select one: a. varies inversely with the distance from the center of Earth. by. v

aries inversely with the square of the distance from the center of Earth. c. is a constant that is independent of altitude d. varies directly with the distance from the center of Earth.
Physics
1 answer:
vladimir1956 [14]3 years ago
7 0

Answer:

b. varies inversely with the square of the distance from the center of Earth.

Explanation:

Comparing the Newton's law of universal gravitation and second law of motion;

from Newton's second law of motion,

F = ma ............. 1

from New ton's law of universal gravitation,

F = \frac{GMm}{r^{2} } ........... 2

Equating 1 and 2, we have;

mg =  \frac{GMm}{r^{2} }

g = \frac{GM}{r^{2} }

Therefore, the acceleration due to gravity near Earth, g, is inversely proportional to the square of the distance from the center of Earth.

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According to the intuitive guess you just made, is the overall momentum of the two-cart system after the collision greater than,
Aloiza [94]

Answer:

It is equal to the overall momentum before collision, so far no external object is involved.

Explanation:

Momentum is always conserved during collision as a rule. This is equal to the product of the mass and velocity. Thank you.

5 0
3 years ago
A 25 N force stretches a spring 280 cm. What was the spring constant? ​
boyakko [2]

Answer:

  1. F= 25N
  2. ∆l=280cm
  3. K=?
  4. you apply the formula = K:F/∆l
  5. = 0,089N/cm
4 0
3 years ago
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Joe is hiking through the woods when he decides to stop and take in the view. He is particularly interested in three objects: a
Novosadov [1.4K]

Answer:

A) correct answer is C,   B)   correct answer is b  and C) The correct answer is b

Explanation:

In the exercises of geometric optics, the equation of the constructor tells us the location of the image.

        1 / f = 1 / p + 1 / q

where f is the focal length of the cornea-crystalline system, p and q are the distances to the object and the image.

In this case, the distance to the image on the retina is constant, about 3 cm. Therefore depending on the distance to the object) p = the focal length must change

        1 / q = 1 / f 1 / p

let's apply this expression to our case

A) indicates that the tree is at a medium distance

so that the image is formed on the retina THE SAME AS

correct answer is C

B) The squirrel is at a smaller distance (p ') than the tree (p), therefore if we substitute in the equation above we find that q must decrease. Consequently the image is in front of the retina

The mountain is very far, suppose in infinity, so the image is BEHIND THE RETINA

therefore the correct answer is b

C) The squirrel is very close so the curvature of the lens INCREASES, resulting in a DECREASE in the focal length

The correct answer is b

6 0
3 years ago
Please help!?!?
Vanyuwa [196]

Since bulb is connected in the closed circuit at the position of D

as well as switch B is also closed in that position so the current will flow through the bulb and bulb will glow in that position

So the most appropriate correct option will be

D. The light bulb will be on

5 0
3 years ago
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Which of the following is an example of work being done on an object?
tensa zangetsu [6.8K]

Answer:

d. All of these

Explanation:

work is said to be done when a force is applied to an object through a certain distance. the SI unit of workdone is joules or newton per meter

mathematically

workdone = force x distance.

from the answers,  work is being done because there is force applied in a certain distance.

  • from wagon is used to carry vegetables from a garden.
  • pulley is used to get water from a well.
  • hammer is used to remove a nail from a wall.

4 0
3 years ago
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