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Inessa05 [86]
3 years ago
15

A student determines a value for a force using the formula F = k I l.

Physics
1 answer:
kramer3 years ago
5 0

Answer:

maybe dyne.......................

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Can an object be moving downward and have an upward acceleration
dusya [7]

Answer: no

Explanation:

because the object is moving downwards so it will be  called decceleration . which is the opposite of acceleration .

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What is the amount of displacement of a runner who runs exactly 2 laps around a 400 meter track?
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Displacement is the distance and direction from the start point to the end point. Our runner finished exactly where he started. His displacement is zero.
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3 years ago
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In the standing waves experiment, the string has a mass of 31.2 g and a length of 0.7 m. The string is connected to a mechanical
mestny [16]

Answer:

linear density of the string = 4.46 × 10⁻⁴ kg/m

Explanation:

given,

mass of the string = 31.2 g

length of string = 0.7 m

linear density of the string = \dfrac{mass\ of\ string}{length}

linear density of the string = \dfrac{31.2\times 10^{-3}\ kg}{0.7\ m}

linear density of the string = 44.57 × 10⁻³ kg/m

linear density of the string = 4.46 × 10⁻⁴ kg/m

7 0
3 years ago
If the voltage output of a digital manifold absolute pressure (MAP)sensor is 2 volts, the approximate engine vacuum is _______ i
LenaWriter [7]
The correct answer to this question is 15
3 0
3 years ago
For a specific volume of 0.2 m3/kg, find the quality of steam if the absolute pressure is (a) 40 kPa and (b) 630 kPa. What is th
ICE Princess25 [194]

Answer:

x=0.0498

x'=0.659

Explanation:

Specific Volume V=0.2m_3/kg

Absolute Pressure (a) P_a= 40kpa

Giving

T_a=75.87

v_f=1.265*10^{-3}m^3/kg

v_g=3.993m^3/kg

                               (b) P_a= 630kpa

Giving

T_b=160.13C

v_f'=1.10282*10^{-3} m^3/kg

v_g'=0.30286 m^3/kg

(a)

Generally the equation for quality of Steam X  is mathematically given by

x=\frac{v-v_f}{v_g-v_f}

x=\frac{0.2-1.0265*10^{-3}}{3.993-1.0265*10^{-3}}

x=0.0498

(b)

Generally the equation for quality of Steam X  is mathematically given by

x'=\frac{v-v_f'}{v_g'-v_f'}

x'=\frac{0.2-1.10*10^{-3}}{3.30-1.1*10^{-3}}

x'=0.659

4 0
3 years ago
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