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BARSIC [14]
3 years ago
12

Mendeleev gave the name eka-aluminum to an A. compound containing aluminum. B. mixture of aluminum and an unknown element. C. un

known element he predicted would have properties similar to those of aluminum. D. rare isotope of aluminum.

Physics
2 answers:
PolarNik [594]3 years ago
5 0

Answer: C. unknown element he predicted would have properties similar to those of aluminum.

Explanation: Mendeleev arranged the elements in order of increasing atomic masses. He left spaces for the elements that were predicted to exist, but were not discovered.

One space was left below Aluminum where an element of mass 70 was predicted to exist with properties similar to Aluminum. It was referred to as eka-Aluminum.

Later it was named as gallium.


baherus [9]3 years ago
5 0

Mendeleev gave the name eka-aluminum to an <u><em>C. unknown element he predicted would have properties similar to those of aluminum </em></u>

<h3>Further explanation </h3>

The periodic system of elements is an arrangement of elements classified based on similar properties and their atomic number order.

The periodic system is divided into groups (vertical order) and periods (horizontal order)

There are some scientists who do the grouping of elements, mostly based on the relative atomic mass

  • 1. Dobereiner

These scientists grouped the elements into groups of three elements called the Triade

  • 2. Newlands

These scientists arrange elements based on their relative atomic mass increases called the octave law. Similarities between the elements occur in elements that  have a difference of 1 octave  (elements 1 and 8, elements 2 and 9, elements 3 and 10 etc.)

  • 3. Mendeleev

These scientists group elements based on their relative atomic mass increases.

Mendeleev placed elements that have similar properties in one group (vertical direction) and based on the increase in relative atomic mass in one period

In the periodic system made by Mendeleev, there are some parts in the group that are left blank because the element has not been found but is predicted to have the same properties as the elements in that group.

The Mendeleev periodic system is useful after the discovery of new elements which had similar properties in accordance with Mendeleev's predictions.

In group III, under the Al element, Mendeleev empties the unknown element, but it is predicted to have similar properties with aluminum and is given the name eka-aluminum. This element was later discovered and named gallium (Ga) with atomic number 31 and relative atomic mass of 69.72

<h3>Learn more </h3>

electron affinity

brainly.com/question/1440853

Identify the group number in the periodic table

brainly.com/question/2014634

the charge on each ion in the compounds

brainly.com/question/5880856

Keywords: element, group, period, eka-aluminum, gallium, periodic system

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Answer:

4.62 N-s

Explanation:

recall that the formula for impulse is given by

Impulse = Force x change in time

in our case, we are given

Force = 14 N

change in time = 0.33s

Simply substituting the above into the equation for impulse, we get

Impulse = Force x change in time

Impulse = 14 x 0.33

= 4.62 N-s

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A wire that is 0.65 m long and carrying a current of 8.2 A is at right angles to a uniform magnetic field. The force on the wire
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Answer:

0.075 T

Explanation:

When a current-carrying wire is immersed in a region with magnetic field, the wire experiences a force, given by

F=ILB sin \theta

where

I is the current in the wire

L is the length of the wire

B is the strength of the magnetic field

\theta is the angle between the direction of I and B

In this problem we have:

L = 0.65 m is the length of the wire

I = 8.2 A is the current in the wire

F = 0.40 N is the force experienced by the wire

\theta=90^{\circ} since the current is at right angle with the magnetic field

Solving the formula for B, we find the strength of the magnetic field:

B=\frac{F}{IL sin \theta}=\frac{0.40}{(8.2)(0.65)(sin 90^{\circ})}=0.075 T

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A scientist bred fruit flies in two separate containers with different food sources for many generations. When she put the fruit
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Fruit flies prefer mates adapted to the same food source.

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Trivia Time!! At what velocity does light move?
Maslowich

Explanation:

Light Light from a moving source travels at 300,000 km/sec (186,000 miles/sec).

Note:

The Speed of Light Is Constant.

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2 years ago
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A 3.5 kg object moving in two dimensions initially has a velocity v1 = (12.0 i^ + 22.0 j^) m/s. A net force F then acts on the o
lys-0071 [83]

Answer:

The work done by the force is 820.745 joules.

Explanation:

Let suppose that changes in potential energy can be neglected. According to the Work-Energy Theorem, an external conservative force generates a change in the state of motion of the object, that is a change in kinetic energy. This phenomenon is describe by the following mathematical model:

K_{1} + W_{F} = K_{2}

Where:

W_{F} - Work done by the external force, measured in joules.

K_{1}, K_{2} - Translational potential energy, measured in joules.

The work done by the external force is now cleared within:

W_{F} = K_{2} - K_{1}

After using the definition of translational kinetic energy, the previous expression is now expanded as a function of mass and initial and final speeds of the object:

W_{F} = \frac{1}{2}\cdot m \cdot (v_{2}^{2}-v_{1}^{2})

Where:

m - Mass of the object, measured in kilograms.

v_{1}, v_{2} - Initial and final speeds of the object, measured in meters per second.

Now, each speed is the magnitude of respective velocity vector:

Initial velocity

v_{1} = \sqrt{v_{1,x}^{2}+v_{1,y}^{2}}

v_{1} = \sqrt{\left(12\,\frac{m}{s} \right)^{2}+\left(22\,\frac{m}{s} \right)^{2}}

v_{1} \approx 25.060\,\frac{m}{s}

Final velocity

v_{2} = \sqrt{v_{2,x}^{2}+v_{2,y}^{2}}

v_{2} = \sqrt{\left(16\,\frac{m}{s} \right)^{2}+\left(29\,\frac{m}{s} \right)^{2}}

v_{2} \approx 33.121\,\frac{m}{s}

Finally, if m = 3.5\,kg, v_{1} \approx 25.060\,\frac{m}{s} and v_{2} \approx 33.121\,\frac{m}{s}, then the work done by the force is:

W_{F} = \frac{1}{2}\cdot (3.5\,kg)\cdot \left[\left(33.121\,\frac{m}{s} \right)^{2}-\left(25.060\,\frac{m}{s} \right)^{2}\right]

W_{F} = 820.745\,J

The work done by the force is 820.745 joules.

6 0
3 years ago
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