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Olin [163]
3 years ago
13

Using the picture below, compare and contrast the plant cell and the animal cell (What do they have different? What do they have

in common

Chemistry
1 answer:
STALIN [3.7K]3 years ago
6 0

Answer:

Animal cell lacks chloroplasts and a cell wall

Explanation:

Unlike animal cells, plant cells have chloroplasts and a cell wall. In a plant cell, the chloroplasts work to use photosynthesis in order to turn light into energy for the plant cell. Animal cells do not utilize light energy, and therefore do not carry out photosynthesis and do not have chloroplasts.

Additionally, the plant cell has a protective cell wall and a cell membrane, while animal cells only have a cell membrane. This is because the plant cells' cell wall provides additional strength and protection against outside factors, such as osmosis.

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`You have to be careful about pouring drano down your pipes since it is mainly hydrochloric acid--you can't do it if they are ma
Zanzabum

Answer:

6.67 moles

Explanation:

Given that:-

Moles of hydrogen gas produced = 10.0 moles

According the reaction shown below:-

2Al + 6HCl\rightarrow 2AlCl_3 +3H_2

3 moles of hydrogen gas are produced when 2 moles of aluminium undergoes reaction.

Also,

1 mole of hydrogen gas are produced when \frac{2}{3} moles of aluminium undergoes reaction.

So,

10.0 moles of hydrogen gas are produced when \frac{2}{3}\times 10.0 moles of aluminium undergoes reaction.

<u>Moles of Al needed  = \frac{2}{3}\times 10.0 moles = 6.67 moles</u>

6 0
3 years ago
What volume of lead (of density 11.3 g/cm3 ) has the same mass as 395 cm3 of a piece of redwood (of density 0.38 g/cm3 )? Answer
Zepler [3.9K]
d_{1}=\frac{m}{V_{1}}\\\\&#10;V_{1}=395cm^{3}\\&#10;d_{1}=0,38\frac{g}{cm^{3}} \ \ \ \ \Rightarrow \ \ \ \ m=395cm^{3}*0,38\frac{g}{cm^{3}}=150,1g\\\\\\&#10;d_{2}=\frac{m}{V_{2}}\\\\&#10;m=150,1g\\&#10;d_{2}=11,3\frac{g}{cm^{3}} \ \ \ \ \Rightarrow \ \ \ \ V_{2}=\frac{150,1g}{11,3\frac{g}{cm^{3}}}\approx13,28cm^{3}
8 0
3 years ago
Consider the following reaction between mercury(II) chloride and oxalate ion.
Alina [70]

<u>Answer:</u> The rate law of the reaction is \text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)

Rate law expression for the reaction:

\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b

where,

a = order with respect to HgCl_2

b = order with respect to C_2O_4^{2-}

Expression for rate law for first observation:

3.2\times 10^{-5}=k(0.164)^a(0.15)^b  ....(1)

Expression for rate law for second observation:

2.9\times 10^{-4}=k(0.164)^a(0.45)^b  ....(2)

Expression for rate law for third observation:

1.4\times 10^{-4}=k(0.082)^a(0.45)^b  ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-5}=k(0.246)^a(0.15)^b  ....(4)  

Dividing 2 from 1, we get:

\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2

Dividing 2 from 3, we get:

\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{(0.164)^a(0.45)^b}{(0.082)^a(0.45)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2

3 0
3 years ago
Name the following lonic Compounds using the lonic naming rules. Remember, place the metal's name
liq [111]
1.Calcium Chloride
2.Lithium Bromide
3.Beryllium Sulfide
4.Lithium Fluoride
5. Potassium hydroselenide
6. Strontium phosphide
7.Barium Chloride
8.Iron Oxide
9.Iron
10.?
11.Copper Nitride
6 0
3 years ago
What mass of cu(s) is electroplated by running 26.5 a of current through a cu2+(aq) solution for 4.00 h?
kramer
T = 14400 s 
26.5 x 14400=381600 C 
381600/96500=3.95 Faradays 
Cu2+ + 2e- = Cu 
3.95 faradays ( 1 mol/ 2 Faradays) = 1.97
mass = 1.97 x 63.55 g/mol=125 g 

moles Au = 33.1 / 196.967 g/mol=0.168 
Au+ + 1e- = Au 
0.168 ( 1 Faraday/ 1mol)= 0.168 Faraday 
0.168 x 96500=16217 Coulombs 
16217 / 5.00=3243 s => 54 min
7 0
3 years ago
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