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GalinKa [24]
2 years ago
5

Please help me with this question,giving the first correct answer brainliest

Physics
2 answers:
Bess [88]2 years ago
7 0

Answer:

Your answer is A

Explanation:

Anettt [7]2 years ago
3 0

Answer:

Mixture

Explanation Just did test :)

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A car achieves a velocity 50 meters per second after 5 seconds. What is the Car's acceleration?
Reptile [31]

Answer: 10 m/s

Explanation: Velocity/Time

50/5= 10

:)

7 0
3 years ago
If a 15g irregular shaped object is submerged in a graduated cylinder of water, the level rises from 10 ml to 25 ml, what is the
SashulF [63]

Answer:

one im so sry i have no idea. I have been researshing for about 30min and i cant find anything im so sry:/

Explanation:

6 0
3 years ago
A plane is landing at an airport. The plane has a massive amount of kinetic energy due to it's motion. When the plane lands, it
marshall27 [118]

Answer:

A. The brakes used a coil system to convert the kinetic energy into potential energy stored in the brakes

Explanation:

Based on the law of conservation of energy, the brakes used a coil system to convert the kinetic energy into potential energy stored in the brakes.

The law of conservation of energy states that energy is neither created nor destroyed in a system but it is transformed from one form to another.

As the airplane slows down, the kinetic energy which is presented in the motion of the plane is gradually converted to potential energy.

The potential energy is the energy due to the position of a body.

8 0
2 years ago
An open organ pipe of length 0.47328 m and another pipe closed at one end of length 0.702821 m are sounded together. What beat f
sineoko [7]

Answer:

fb = 240.35 Hz

Explanation:

In order to calculate the beat frequency generated by the first modes of each, organ and tube, you use the following formulas for the fundamental frequencies.

Open tube:

f=\frac{v_s}{2L}         (1)

vs: speed of sound = 343m/s

L: length of the open tube = 0.47328m

You replace in the equation (1):

f=\frac{343m/s}{2(0.47228m)}=362.36Hz      

Closed tube:

f'=\frac{v_s}{4L'}

L': length of the closed tube = 0.702821m

f'=\frac{343m/s}{4(0.702821m)}=122.00Hz

Next, you use the following formula for the beat frequency:

f_b=|f-f'|=|362.36Hz-122.00Hz|=240.35Hz

The beat frequency generated by the first overtone pf the closed pipe and the fundamental of the open pipe is 240.35Hz

7 0
3 years ago
) The centre of a mass, m, is at a distance, r, from the centre of a larger mass M. Assuming there are no other masses present,
ivanzaharov [21]

Answer:

U = - G m M / r

Explanation:

The gravitational potential energy is given by the expression

         U = - G m₁ m₂ / r

dodne G is the gravitational cosntnate (G = 6.67 10⁻¹¹¹), m and m are the mass of the bodies involved

subtype the given values

         U = - G m M / r

8 0
3 years ago
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