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3 years ago

Which of the following statements CANNOT be supported by Kepler's laws of planetary motion?

Physics

2 answers:

horsena [70]3 years ago

8 0

Answer:

B) A planet's speed as it moves around the sun will not be the same in six months.

Explanation:

A planet's speed as it moves around the sun will not be the same in six months, is a statement that CANNOT be supported by Kepler's laws of planetary motion.

Alisiya [41]3 years ago

6 0

The statement ‘A planet's speed as it moves around the sun will not be the same in six months’ cannot be supported by Kepler’s law of planetary motion.

Answer: Option B

<u>Explanation: </u>

Johannes Kepler stated three significant laws related to planetary motion. The option A statement is true. Because, the first law defines that the distance between the planet and the sun will not be same as they are rotating around the sun in elliptical orbits.

The third law states that the ratio of square of time taken to complete one orbital rotation by two planets will be equal to the ratio of cube of the distances of the two planets from the sun.

So, according to third law, the statements (c) and (d) can also be supported by Kepler's law. Hence, option (b) is not supported by Kepler's law.

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3 years ago

Which of the following is NOT a correct statement?*

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2 years ago

A light spring stretches 0.13 m when a 0.35 kg mass is hung from it. The mass is pulled down from this equilibrium position an a

Alenkasestr [34]

Answer:

v = 1.30 m/s

Explanation:

given,

mass hung = 0.35 Kg

spring stretched when load is hanged (x)= 0.13 m

now,

weight of the mass attached = Kx

m g = k x

0.35 x 9.8 = k x 0.13

k = 26.38 N/m

now, using conservation of energy

$\dfrac{1}{2}mv^2 = \dfrac{1}{2}kx'^2$

$v = \sqrt{\dfrac{kx'^2}{m}}$

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$v = \sqrt{1.6958}$

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3 years ago

A tiger travels 3m/s^2 for 4.1s,what was its initial speed if it's final speed was 55k/h?

zaharov [31]

Acceleration a=3m/s^2
time t= 4.1seconds
Final velocity V= 55km/h
initial velocity U= ?
First convert V to m/s
36km/h=10m/s
55km/h= 55*10/36=15.28m/s
Using the formula V= U+at
U= V-at
U= 15.28-3*4.1=15.28-12.3=2.98m/s
Initial velocity U= 2.98m/s or 10.73km/h (Using the conversion rate 36km/h=10m/s)

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3 years ago