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11111nata11111 [884]

2 years ago

11

Which ground rule for group work was broken in the following scenario?

2 answers:

Studentka2010 [4]2 years ago

6 0

I think the answer would be Equal Responsibility as the paragraph did not mention Antonia presenting their work with Jan and Finn.

SpyIntel [72]2 years ago

5 0

Answer:

йцу21241

Explanation:

ere taking their seats. Finn and Jan presented the progress they had made on the project since the last meeting. Everyone engaged in the subsequent discussions, asking questions and offering ideas.

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Which of the following is not part of the control system? steering wheel exhaust pipe brake accelerator

Fiesta28 [93]

Answer:

Brakes unevenly adjusted: Brakes pulling in one direction or the other can lead to a skid. Tires with worn tread: Tread is necessary for traction in wet weather

Explanation:

7 0

2 years ago

ALGEBRA Find x and the measures of the unknown sides of each triangle.

valentina_108 [34]

9514 1404 393

Answer:

12. x = 11; sides are 29

13. x = 5; sides are 25

Explanation:

12. The marked sides are equal length, so ...

3x -4 = 2x +7

x = 11 . . . . . . . . add 4-2x

2x+7 = 2(11)+7 = 29 . . . side lengths

__

13. The marked sides are equal length, so ...

6x -5 = 5x

x = 5 . . . . . . . add 5-5x

5x = 5(5) = 25 . . . side lengths

3 0

3 years ago

victus00 [196]

Explanation:

v(speed)=10/120=0.08m/s

3 0

2 years ago

Read 2 more answers

Please guys help me plz for god sake plz plz guys plz plz plz i will mark u as a brainlist plz

victus00 [196]

Answer:

Explanation:

The complete sequence of motions and activities required to complete one work cycle.

8 0

2 years ago

A 1.0 kg mass is attached to the end of a vertical ideal spring with a force constant of 400 N/m. The mass is set in simple harm

Marina86 [1]

Answer:

$v(0)=2m/s$

Explanation:

The instantaneous velocity of a point mass that executes a simple harmonic movement is given by:

$v(t)=\omega *A*cos(\omega t + \phi)$

Where:

$\omega=Angular\hspace{3}frequency\\A=Amplitude\\\phi=Initial\hspace{3}phase$

Express the amplitude in meters:

$10cm*\frac{1m}{100cm} =0.1m$

The angular frequency can be found using the next equation:

$\omega=\sqrt{\frac{k}{m} }$

Using the data provided:

$\omega=\sqrt{\frac{400}{1} } =20$

At the equilibrium position:

$\phi=0$

$v(0)=20*(0.1)cos(20*0+0)=2*cos(0)=2*1=2m/s$

6 0

3 years ago