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Neko [114]
3 years ago
7

What is a chromatogram?please help me out Thank you​

Chemistry
2 answers:
weqwewe [10]3 years ago
7 0

Answer:

Chromatography is a technique used to separate mixture of chemical substances into its individual compounds.

Explanation:

Aleksandr [31]3 years ago
5 0

Answer:

a visible record (such as a series of colored bands, or a graph) showing the result of separation of the components of a mixture by chromatography.

Explanation:

Chromatography is a laboratory technique for the separation of a mixture. The mixture is dissolved in a fluid called the mobile phase, which carries it through a system on which is fixed a material called the stationary phase.

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When two gases or two liquids form a solution, the substance that is present in the largest amount is the?
skad [1K]
Is the solvent (Hope this helped)
4 0
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What three types of Protists have been discovered
frosja888 [35]

Answer:

the answer is D

Explanation:

but hope this helps

8 0
3 years ago
Read 2 more answers
What is the ph of a solution labeled .30 trimethylamine k for trimethylamine is 7.42 x 10^4
valentina_108 [34]

Answer:the pH is 12

Explanation:

First We need to understand the structure of trimethylamine

Due to the grades of the bond in the nitrogen with a hybridization sp3 is 108° approximately, then is generated a dipole magnetic at the upper side of the nitrogen, this dipole magnetic going to attract a hydrogen molecule of the water making the water more alkaline

C3H9N+ H2O --> C3H9NH + OH-

k=\frac{[C3H9NH]*[OH-]}{[C3H9N]}

Then:

The concentration of the trimethylamine is 0.3 and the concentration of the ion C3H9NH is equal to the OH- relying on the stoichiometric equation. We could find the concentration of the OH- ion with the square root of the multiplication between k and the concentration of trimethylamine

[OH-]=\sqrt{ 0.3*7.42x10^{-4}}

[OH-]=0.01

pH=14-(-log[OH-])

pH=12

5 0
3 years ago
QUESTION 7
Temka [501]

The student's test average is : 0.92

Total score obtained = 369

Number of tests = 4

Since Each test is exactly 100 points ;

The total score obtainable is (100 × 4) = 400

Average = score obtained / total score obtainable

Average = 369 / 400

Average = 0.9225

Average = 0.92

Learn more : brainly.com/question/9416487?referrer=searchResults

5 0
3 years ago
Determine the volume in mL of 0.37 M HClO4(aq) needed to reach the half-equivalence (stoichiometric) point in the titration of 2
Dimas [21]

Answer:

14.3mL you require to reach the half-equivalence point

Explanation:

A strong acid as HClO₄ reacts with a weak base as CH₃CH₂NH₂, thus:

CH₃CH₂NH₂ + HClO₄ → CH₃CH₂NH₃⁺ + ClO₄⁻

As the reaction is 1:1, to reach the equivalence point you require to add the moles of HClO₄ equal to moles CH₃CH₂NH₂ you add originally. Also, half-equivalence point requires to add half-moles of CH₃CH₂NH₂ you add originally.

Initial moles of CH₃CH₂NH₂ are:

20.8mL = 0.0208L × (0.51mol CH₃CH₂NH₂ / 1L) =

0.0106moles CH₃CH₂NH₂

To reach the half-equivalence point you require:

0.0106moles ÷ 2 = 0.005304 moles HClO₄

As concentration of HClO₄ is 0.37M, volume you require to add 0.005304moles is:

0.005304 moles HClO₄ ₓ (1L / 0.37mol) = 0.0143L =

<h3> 14.3mL you require to reach the half-equivalence point</h3>

7 0
3 years ago
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