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Arada [10]
3 years ago
15

2.

Physics
1 answer:
Julli [10]3 years ago
5 0

Answer: C. Metals are found on the left side of the periodic table.

Explanation:

The periodic table contains vertical columns called as groups and horizontal rows called as periods.

Period 2 contains 8 elements which are lithium, beryllium , boron , carbon, nitrogen, oxygen , fluorine and neon. Only Lithium and beryllium are metals.

Group 18 contains all the noble gases which are all non metals.

Metals are the elements which loose electrons easily and form positive ions. Non-metals are the elements which can gain electrons easily and form negative ions.

Metals are present on left side of the periodic table and as we move to right side of the periodic table , the metallic character decreases and thus non metals are found on the right side of the periodic table.

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A beam of electrons is sent horizontally down the axis of a tube to strike a fluorescent screen at the end of the tube. On the w
slamgirl [31]

Answer:

The answer is 3.

Explanation:

The answer to this question can be found by applying the right hand rule for which the pointer finger is in the direction of the electron movement, the thumb is pointing in the direction of the magnetic field, so the effect that this will have on the electrons is the direction that the middle finger points in which is right in this example.

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I hope this answer helps.

4 0
3 years ago
What occurs when salt is evenly mixed with water
zimovet [89]
The more you mix salt with water the more the salt will dissolve
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3 years ago
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A long, straight, horizontal wire carries a left-to-right current of 40 A. If the wire is placed in a uniform magnetic field of
Drupady [299]

Answer:

4.5\times 10^{-5} T

Explanation:

We are given that

Current in wire=40 A

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We have to find the resultant magnitude of the magnetic field 29 cm above the wire and 29 cm below the wire.

According to Bio-Savart law, the magnetic field exerted by the wire at distance R is given by

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We have R=29 cm=\frac{29}{100}=0.29 m

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B=\sqrt{B^2_1+B^2_2}

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B=\sqrt{(3.5\times 10^{-5})^2+(2.76\times 10^{-5})^2}

B=4.5\times 10^{-5} T

The resultant magnitude of magnetic field is same above and below the wire as it is at same distance.

The resultant magnitude of the magnetic field 29 cm below the wire=4.5\times 10^{-5} T

Hence, the resultant magnitude of the magnetic field 29 cm above  the wire=4.5\times 10^{-5} T

7 0
3 years ago
Find the time taken by body whose rate and distance is 6 miles per hour and 2 miles respectively?
xxTIMURxx [149]

Answer:

12 miles per hour

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7 0
2 years ago
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