Answer:
f = 4000 / 30 sec = 133.3 vibrations/sec
P = 1 / f = .0075 sec period of 1 vibration
Forces that are equal in size but opposite in direction and do not cause a change in an object's movement are called balanced forces.
forces that aren't equal in size and do cause a change in movement (what it seems like you're asking for) are called UNBALANCED FORCES
so answer (in case that wasn't clear, as I'm tired) : unbalanced forces
To solve the problem it is necessary to apply the equations related to the conservation of both <em>kinetic of rolling objects</em> and potential energy and the moment of inertia.
The net height from the point where it begins to roll with an inclination of 30 degrees would be
In the case of Inertia would be given by
In general, given an object of mass m, an effective radius k can be defined for an axis through its center of mass, with such a value that its moment of inertia is
Replacing in Energy conservation Equation we have that
Potential Energy = Kinetic Energy of Rolling Object
Therefore the correct answer is C.
Its simple, you have to plot in an example, but dont get confused with K, the answer its b
Answer:
Explanation:
Let that point be at a distance x from q1
Then Kq1/x^2= Kq2/ (s-x)^2
Taking square roots and simplifying, x =s /[1+(q2/q1)^0.5]
Assuming an identical distance, the rigidity of Q on 2Q is equivalent in value to the rigidity of 2Q on Q. for that reason, had the area R been stored an identical, the two forces could be equivalent. inspite of the shown fact that, via fact the area is being decreased, we could constantly consult with the equation we use to calculate those forces: F = ok(Q1xQ2)/(R^2) because R is squared and is being halved, the final result's that's it being divided by potential of a million/4. for that reason, the rigidity would be expanded by potential of four, and be 4F.
