1) The horizontal range of the bullet is 884 m
2) The maximum height attained by the bullet is 383 m
Explanation:
1)
The motion of the bullet is a projectile motion, which consists of two separate motions:  
- A uniform motion (constant velocity) along the horizontal direction  
- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction  
From the equation of motions along the x- and y- directions, it is possible to find an expression for the horizontal range covered by a projectile, and it is:

where
u is the initial speed of the projectile
 is the angle of projection
 is the angle of projection
 is the acceleration of gravity
 is the acceleration of gravity
For the bullet in the problem, we have
u = 100 m/s (initial speed)
 (angle)
 (angle)
Solving the equation, we find the horizontal range:

2)
To find the maximum height, we have to analyze the vertical motion of the bullet. We can do it by using the following suvat equation:

where
 is the vertical velocity of the bullet after having covered a vertical displacement of
 is the vertical velocity of the bullet after having covered a vertical displacement of 
 is the initial vertical velocity
 is the initial vertical velocity
 is the acceleration (negative, since it points downward)
 is the acceleration (negative, since it points downward)
The vertical component of the initial velocity is given by

Also, the maximum height s is reached when the vertical velocity becomes zero,

Substituting into the equation and re-arranging for s, we find the maximum height:

Learn more about projectile motion:
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