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Talja [164]
4 years ago
15

Energy transfer by convection is usually restricted to what type of substance?

Physics
2 answers:
dedylja [7]4 years ago
5 0

<u>Answer:</u> The correct answer is fluids.

<u>Explanation:</u>

There are 3 modes of heat transfer that happens:

1. <u>Conduction:</u> In this type of heat transfer, heat is transferred when there is direct contact between the two object.

2. <u>Convection:</u> In this type of heat transfer, heat is transferred when there is a movement of fluid (liquid or gas).

3. <u>Radiation:</u> In this type of heat transfer, heat is transferred when there is direct transfer of energy through space.

Hence, convection is only restricted to fluids which are liquids and gases.

just olya [345]4 years ago
3 0

the anwser is d) fluids

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The volume of a gas is reduced from 4 l to 0.5 l while the temperature is held constant. How does the gas pressure change?
shusha [124]

Answer:

The pressure increases by a factor 8

Explanation:

For a gas held at constant temperature, Boyle's law can be applied. It states that the product of the gas pressure and the gas volume is constant, so we can write:

p_1 V_1 = p_2 V_2

where

p_1 is the initial pressure

p_2 is the final pressure

V_1 is the initial volume

V_2 is the final volume

For the gas in this problem, the volume is reduced from

V_1 = 4 L

to

V_2 = 0.5 L

so we can rewrite the equation as

\frac{p_2}{p_1}=\frac{V_1}{V_2}=\frac{4 L}{0.5 L}=8

this means that the pressure of the gas will increase by a factor 8.

5 0
4 years ago
4500 miles to inches
Volgvan

Answer:

2.8512*10^8 inches

Explanation:

Seeing as the ratio for miles to inches is 1 mile = 63360 inches, set up an equation. 1 mile / 63360 inches = 4500 miles / x inches. Cross multiply and simplify to 2.8512*10^8 inches. Hope this helps! :)

6 0
3 years ago
What is the efficiency of an engine that exhausts 440 J of heat to a cold reservoir and receives 570 J of heat from a hot reserv
katrin2010 [14]

Answer:

Efficiency = 77%

Explanation:

Input energy = 570 J

Output energy = 440 J

To find the efficiency;

Efficiency = \frac {Out-put \; energy}{In-put \; energy} * 100

Substituting into the equation, we have;

Efficiency = \frac {440}{570} * 100

Efficiency = 0.7719 * 100

Efficiency = 77.19 ≈ 77%

Therefore, the efficiency of the engine is 77 percent.

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3 years ago
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