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Talja [164]
4 years ago
15

Energy transfer by convection is usually restricted to what type of substance?

Physics
2 answers:
dedylja [7]4 years ago
5 0

<u>Answer:</u> The correct answer is fluids.

<u>Explanation:</u>

There are 3 modes of heat transfer that happens:

1. <u>Conduction:</u> In this type of heat transfer, heat is transferred when there is direct contact between the two object.

2. <u>Convection:</u> In this type of heat transfer, heat is transferred when there is a movement of fluid (liquid or gas).

3. <u>Radiation:</u> In this type of heat transfer, heat is transferred when there is direct transfer of energy through space.

Hence, convection is only restricted to fluids which are liquids and gases.

just olya [345]4 years ago
3 0

the anwser is d) fluids

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A ball is thrown vertically up from the edge of a cliff with a speed of 8 m/s, how high is
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Explanation:

s=d/t

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d=8×16.4

d=131.2

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3 years ago
A commuter train passes a passenger platform at a constant speed of 40.4 m/s. The train horn is sounded at its characteristic fr
mihalych1998 [28]

(a) -83.6 Hz

Due to the Doppler effect, the frequency of the sound of the train horn appears shifted to the observer at rest, according to the formula:

f' = (\frac{v}{v\pm v_s})f

where

f' is the apparent frequency

v = 343 m/s is the speed of sound

v_s is the velocity of the source of the sound (positive if the source is moving away from the observer, negative if it is moving towards the observer)

f is the original frequency of the sound

Here we have

f = 350 Hz

When the train is approaching, we have

v_s = -40.4 m/s

So the frequency heard by the observer on the platform is

f' = (\frac{343 m/s}{343 m/s - 40.4 m/s})(350 Hz)=396.7 Hz

When the train has passed the platform, we have

v_s = +40.4 m/s

So the frequency heard by the observer on the platform is

f' = (\frac{343 m/s}{343 m/s + 40.4 m/s})(350 Hz)=313.1 Hz

Therefore the overall shift in frequency is

\Delta f = 313.1 Hz - 396.7 Hz = -83.6 Hz

And the negative sign means the frequency has decreased.

(b) 0.865 m

The wavelength and the frequency of a wave are related by the equation

v=\lambda f

where

v is the speed of the wave

\lambda is the wavelength

f is the frequency

When the train is approaching the platform, we have

v = 343 m/s (speed of sound)

f = f' = 396.7 Hz (apparent frequency)

Therefore the wavelength detected by a person on the platform is

\lambda' = \frac{v}{f'}=\frac{343 m/s}{396.7 Hz}=0.865m

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The correct answer is:

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