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xz_007 [3.2K]
3 years ago
9

Describe the relationship between volume and temperature. Use specific information from your data and/or graph to illustrate thi

s relationship
Chemistry
1 answer:
zalisa [80]3 years ago
8 0
I don't have a graph but here's what I think. The relationship is that the volume will change depending on the temperature. So think of water for an example. The volume of it will stay the same at room temperature, but if you put a glass of it in the freezer for a few hours, take it out, measure the volume, the volume would have changed greatly. Or heating and evaporating the water will do the same.
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For the following pairs of ions, use the concept that a chemical compound must have a net charge of zero to predict the formula
Dafna11 [192]

\\ \sf\longmapsto FeP

\\ \sf\longmapsto Fe_2S_3

\\ \sf\longmapsto FeCl_2

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\\ \sf\longmapsto MgO

\\ \sf\longmapsto Mg_3N_2

\\ \sf\longmapsto Na_3P

\\ \sf\longmapsto Na_2S

\\ \sf\longmapsto CoO

\\ \sf\longmapsto Co_2S_3

\\ \sf\longmapsto AlCl_3

\\ \sf\longmapsto CsBr

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4 0
3 years ago
Which group of elements readily loses two electrons to form a compound?
nexus9112 [7]
The alkaline earth metals (the second group) because their ion charge is +2
8 0
3 years ago
One of the waste products produced by kidneys is creatinine. A healthy range ofcreatinine in human blood is between 0.50 mg/dL a
Anna35 [415]

The normal range of creatinine in human blood is between 0.50 mg/dL and 1.1 mg/dL. The patient's blood has a concentration of 0.0082 g/L. Let's convert that value into mg/dL.

We kwnot that there are 1000 mg in 1 g. And there are 10 dL in 1 L. We have to use those conversions.

1000 mg = 1 g 10 dL = 1 L

0.0082 g/L = 0.0082 g/L * 1000 mg/g = 8.2 mg/L * 1 L/ (10 dL) = 0.82 mg/dL

0.0082 g/L = 0.82 mg/dL

0.50 mg/dL < 0.82 mg/dL < 1.1 mg/dL

Answer: The concentration of creatinine = 0.82 mg/dL. It is in the normal range.

8 0
1 year ago
If 250.0 g of water at 30.0 °C cool to 5.0 °C, how many kilojoules of energy did the water lose?
Y_Kistochka [10]

Answer:

-26.125 kj

Explanation:

Given data:

Mass of water = 250.0 g

Initial temperature = 30.0°C

Final temperature = 5.0°C

Amount of energy lost = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 5.0°C - 30.0°C

ΔT = -25°C

Specific heat of water is 4.18 j/g.°C

Now we will put the values in formula.

Q = m.c. ΔT

Q = 250.0 g × 4.18 j/g.°C × -25°C

Q = -26125 j

J to kJ

-26125 j ×1 kj /1000 j

-26.125 kj

5 0
3 years ago
Which criteria determine whether a heterogeneous mixture is a colloid or a suspension?
vivado [14]
Correct Answer: Option B: <span>whether the particles do not settle for an extended period of time

Reason:
Particle size in colloidal solution ranges from 1-100 nm, while that is suspension is more than 100 nm. Due to large particle size, particles in suspension settle down, upon standing for long. Thus, the best </span>criteria determine whether a heterogeneous mixture is a colloid or a suspension is to check <span>whether the particles do not settle for an extended period of time</span>
5 0
3 years ago
Read 2 more answers
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