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kolezko [41]
3 years ago
15

A 3 kg penguin is pushed by his penguin friends who give him an initial speed vo at the top of a 30 m hill. The penguin is hopin

g this will be enough initial speed that he can make it all the way down this hill and up the next hill which is 45 m tall. Neglecting friction and air resistance, what does the initial speed need to be for him to make it up this second hill?
Physics
1 answer:
Strike441 [17]3 years ago
7 0

Answer:

This question can be answered by using conversation of energy.

K_1 + U_1 = K_2 + U_2

\frac{1}{2}mv_{0}^2 + mgh_1 = 0 + mgh_2

\frac{1}{2}(3)v_0^2 + (3)(9.8)(30) = (3)(9.8)(45)\\\frac{1}{2}(3)v_0^2 = 441\\v_0^2 = 294\\v_0 = 17.14 m/s

Explanation:

Note that we take K_2 = 0 because we are looking for the minimum initial speed for the penguin to reach the top of the second hill. Any other speed more than this will already be enough for him.

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As we know that in transformers we have

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here we know that

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N_s = 600 coils

now from above equation we will have

\frac{17500}{350000} = \frac{600}{N_p}

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3 years ago
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Answer:

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You exert a force of 75 newtons on a rock. You push and you push, but you can’t budge it. You are exhausted! How much work did y
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4 0
3 years ago
A 12,000-N car is raised using a hydraulic lift, which consists of a U-tube with arms of unequal areas, filled with oil and capp
Bond [772]

Answer:

= 925.92 N

≅ 926N

Explanation:

Pressure due to car = pressure due to applied force  

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force = 12000 * 25/ 324

= 925.92 N

For equilibrium

Pressure1 = Pressure2

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so, F2 = Applied force to lift car = 925.92 N

Pascal's principle

Pressure1 = Pressure2

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A2 =Pi(0.18)²

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7 0
3 years ago
A 6.00 g lead bullet traveling at420 m/s is stopped by a large
Westkost [7]

Answer:

The increase in temperature of the bullet is 351.1 kelvin

Explanation:

First, we should find the kinetic energy of the bullet is:

K=\frac{mv^{2}}{2}=\frac{(6\times10^{-3}\,kg)(420\,\frac{m}{s})^{2}}{2}

with m the mass and v the velocity.

K=529.2 J

Now we know that half of the kinetic energy of the bullet is transformed into internal energy, by second's law of thermodynamics that means heat (Q) to raise bullet temperature (T), so:

Q=\frac{K}{2}= 264.6\,J

To know what the increase in temperature is, we should use specific heat of lead:

c=125.604 \frac{J}{kg\.K}

The equation that relates specific heat, change in temperature and mass is:

Q=cm\varDelta T

solving for \varDelta T:

\varDelta T=\frac{Q}{cm}=\frac{264.6}{(125.604)(6\times10^{-3})}

\varDelta T= 351.10\, K

4 0
2 years ago
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