Question

Assume that a clay model of a lion has a mass of 0.225 kg and travels on the ice at a speed of 0.85 m/s. It hits another clay model, which is initially motionless and has a mass of 0.37 kg. Both being soft clay, they naturally stick together.
What is their final velocity?

Answer 1

Answer:

Final velocity will be equal to 0.321 m/sec

Explanation:

We have given mass of clay model of lion $m_1=0.225kg$

Its speed is 0.85 m/sec, so $v_1=0.85m/sec$

Mass of another clay model $m_2=0.37kg$

It is given that second clay is motionless

So its velocity $v_2=0m/sec$

Now according to conservation of momentum

Momentum before collision will be equal to momentum after collision

So $m_1v_!+m_2v_2=(m_1+m_2)v$, here v is velocity after collision

So $0.225\times 0.85+0.37\times 0+(0.225+0.37)v$

$0.595v=0.191$

v = 0.321 m/sec

So final velocity will be equal to 0.321 m/sec