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AURORKA [14]
3 years ago
9

A tuning fork is sounded above a resonating tube (one end closed), which resonates at a length of 0.20 m and again at 0.60 m. If

the tube length were extended further, at what point will the tuning fork again create a resonance condition?

Physics
1 answer:
Nina [5.8K]3 years ago
6 0

To solve this problem we will apply the concepts related to resonance. The velocity with which sound travels in any medium may be determined if the frequency and the wavelength are known. Since the pipe is closed at one end, that produces frequencies ratio 1:3:5, then

n_1 = \frac{V}{4L_1}

Third resonance occurs at 5n_2

n_2 = \frac{V}{4L_2}

At resonance 5n_2=n_1

5\frac{V}{4L_2} = \frac{V}{4L_1}

L_2 = 5L_1

L_2 = 5*0.2

L_2 = 1m

Therefore at 1m will the tuning fork again create a resonance condition

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