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dangina [55]
3 years ago
10

I WILL MARK BRAINLIEST TO EXPLAINED AND CORRECT ANSWER

Physics
1 answer:
Ket [755]3 years ago
6 0
The answer would be: Winter
The Southern hemisphere is tilted to the left, few degrees away from the sun. This condition will result in more(to maximum) exposure to the sunlight, lead to the summer. The condition is the opposite of the northern hemisphere where it has less area that exposed to sunlight, lead to winter.
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Which light waves travel faster radio waves or gamma waves?
qaws [65]

Answer:

In a vacuum all light travels the same speed no matter what the wavelength or frequency. Gamma radiation has a smaller wavelength and larger frequency, radio waves a smaller frequency and larger wavelength.

Explanation:

3 0
3 years ago
Young's experiment is performed with light of wavelength 502 nm from excited helium atoms. Fringes are measured carefully on a s
jok3333 [9.3K]

Answer:

0.88 mm

Explanation:

Given

Wavelength of the atoms, λ = 502 nm = 502*10^-9 m

Radius of the screen away from the double slit, r = 1 m

We know that Y(20) = 11.4*10^-3 m

d = (20 * R * λ) / Y(20)

d = (20 * 1 * 502*10^-9)/11.4*10^-3

d = 1*10^-5 / 11.4*10^-3

d = 0.88 mm

Therefore, the distance of separation between the two slits is 0.88 mm

7 0
4 years ago
Two billiard balls of equal mass move at right angles and meet at the origin of an xy coordinate system. Initially ball A is mov
frez [133]

Answer:

Speed of ball A after collision is 3.7 m/s

Speed of ball B after collision is 2 m/s

Direction of ball A after collision is towards positive x axis

Total momentum after collision is m×4·21 kgm/s

Total kinetic energy after collision is m×8·85 J

Explanation:

<h3>If we consider two balls as a system as there is no external force initial momentum of the system must be equal to the final momentum of the system</h3>

Let the mass of each ball be m kg

v_{1} be the velocity of ball A along positive x axis

v_{2} be the velocity of ball A along positive y axis

u be the velocity of ball B along positive y axis

Conservation of momentum along x axis

m×3·7 = m× v_{1}

∴  v_{1} = 3.7 m/s along positive x axis

Conservation of momentum along y axis

m×2 = m×u + m× v_{2}

2 = u +  v_{2} → equation 1

<h3>Assuming that there is no permanent deformation between the balls we can say that it is an elastic collision</h3><h3>And for an elastic collision, coefficient of restitution = 1</h3>

∴ relative velocity of approach = relative velocity of separation

-2 =  v_{2} - u → equation 2

By adding both equations 1 and 2 we get

v_{2} = 0

∴ u = 2 m/s along positive y axis

Kinetic energy before collision and after collision remains constant because it is an elastic collision

Kinetic energy = (m×2² + m×3·7²)÷2

                         = 8·85×m J

Total momentum = m×√(2² + 3·7²)

                             = m× 4·21 kgm/s

3 0
4 years ago
A 90-kg astronaut is stranded in space at a point 6.0 m from his spaceship, and he needs to get back in 4.0 min to control the s
Stella [2.4K]

Momentum = 0.5 * 4 = 2 
to conclude the man’s velocity after he throws the piece of equipment, divide this number by the man’s mass. 

v = 2/90 

This is about 0.0222 m/s. To know if he can move 6 meters at velocity in 4minutes, use the following equation. 

d = v * t, t = 4 * 60 = 240 s 
d = 2/90 * 240 = 5⅓ meters. 

This is ⅔ of a meter from the spaceship. To know the velocity that he must have to move 6 meter, use the same equation. 

6 = v * 240 
v = 6/240 
This is about 0.00416 m/s. 
His final momentum = 90 * 6/240 = 2.25 


To know the velocity of the package, divide this number by the mass of the package. 
v = 2.25/0.5 = 4.5 m/s

8 0
3 years ago
A parallel-plate capacitor is connected to a battery. What happens to the stored energy if the plate separation is doubled while
zlopas [31]

Answer:

new energy of the capacitor is half that of initial energy

Explanation:

As we know that the energy stored in the capacitor is given as

U = \frac{1}{2}CV^2

here we know that capacitance of parallel plate capacitor is given as

C = \frac{\epsilon_0 A}{d}

V = voltage of battery

so now we have capacitor remains connected to the same battery and the separation between the plates is doubled

so we have

C' = \frac{\epsilon_0 A}{2d}

so now the energy stored between the plates is

U = \frac{1}{2}(\frac{C}{2})V^2

so new energy of the capacitor is half

8 0
4 years ago
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