Speed= distance/time
Speed= 150000m/7200s=20.83m/s(cor.to.2d.p.)
Answer:
Energy stored in the capacitor is
Explanation:
It is given that,
Charge, 
Potential difference, V = 36 V
We need to find the potential energy is stored in the capacitor. The stored potential energy is given by :

U = 0.000027 J

So, the potential energy is stored in the capacitor is
. Hence, this is the required solution.
Answer:
data storage, OLEDS, and wires
Explanation:
Answer:
1/8 x C
Explanation:
The capacitance of parallel plate capacitor
= ε₀ A /d where A is area of plate and d is distance between plate.
for capacitor 1
C = ε₀ A /d
For capacitor 2
radius = R/2
Area = A / 4
Capacitance
= ε₀ (A/4) x ( 1 / 2d )
= ( 1 / 8) x (ε₀ A /d)
= 1/8 x C