Answer:
speed of the car at the bottom of the driveway is 3.8 m/s
Explanation:
given data
mass = 2.1× 10³ kg
distance = 5 m
angle = 20 degree
average friction force = 4 × 10³ N
to find out
find the speed of the car at the bottom of the driveway
solution
we find acceleration a by force equation that is
force = mg×sin20 - friction force
ma = mg×sin20 - friction force
put here value
2100a = 2100 ( 9.8)×sin20 - 4000
a = 1.447 m/s²
so from motion of equation
v²-u² = 2as
here u is 0 by initial speed and v is velocity and a is acceleration and s is distance
v²-0 = 2(1.447)(5)
v = 3.8
speed of the car at the bottom of the driveway is 3.8 m/s
Answer
given,
initial speed of merry-go-round = 0 rad/s
final speed of merry-go-round = 1.5 rad/s
time = 7 s
Radius of the disk = 6 m
Mass of the merry-go-round = 25000 Kg
Moment of inertia of the disk
I = 450000 kg.m²
angular acceleration
we know,
Statements that are true as regards exposure control plan and its updating are;
<em>Updates must have the reflection of changes in tasks as well in procedures.</em>
<em>Updates must reflect changes in positions that affect occupational exposure.</em>
<em>Updates must have the cost of PPE that is needed and necessary to reduce exposure</em>
An exposure control plan can be regarded as the framework for compliance between the employer and the workers.
- This framework give room for the employer to creates a written plan that will help in protecting their workers from bloodborne pathogens.
- This plan gives hope to workers in term of protection when working with their Employer.
- There are some elements that is associated with Exposure Control Plan, and theses are;
- Health hazards as well as risk that is attributed to each product in the worksite.
- Statement of purpose.
- procedures and practices in a written form
- Responsibilities from the Manager, CEO, designated resources and employer.
Therefore, exposure control plan is avenue to protect workers from bloodborne pathogens.
brainly.com/question/1203927?referrer=searchResults
B. evaporation
c. condensation
They are opposite processes that involve the same transfer of energy
Based on the calculations, the average velocity is equal to 360 m/s and the percent difference is equal to 4.72%.
<h3>What is average velocity?</h3>
An average velocity can be defined as the total distance covered by a physical object divided by the total time taken.
<h3>What is an
average?</h3>
An average is also referred to as mean and it can be defined as a ratio of the sum of the total number in a data set to the frequency of the data set.
<h3>How to calculate the
average velocity?</h3>
Mathematically, the average velocity for this data set would be calculated by using this formula:
Average = [F(v)]/n
Vavg = [v₁ + v₂ + v₃ + v₄ + v₅)/5
Since the values of the average velocity from the table are missing, we would assume the following values for the purpose of an explanation:
Substituting the parameters into the formula, we have:
Vavg = [300 + 450 + 500 + 250 + 300)/5
Vavg = 1800/5
Vavg = 360 m/s.
Next, we would calculate the percent difference by using this formula:
![Percent \;difference = \frac{[V_{avg}\;-\;V_{sound}]}{V_{sound}} \times 100](https://tex.z-dn.net/?f=Percent%20%5C%3Bdifference%20%3D%20%5Cfrac%7B%5BV_%7Bavg%7D%5C%3B-%5C%3BV_%7Bsound%7D%5D%7D%7BV_%7Bsound%7D%7D%20%5Ctimes%20100)
Percent difference = [360 - 343]/360 × 100
Percent difference = 17/360 × 100
Percent difference = 0.0472 × 100
Percent difference = 4.72%.
Read more on average here: brainly.com/question/9550536
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