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ella [17]
3 years ago
8

Two balls of equal size are dropped from the same height from the roof of a building. the mass of ball a is twice that of ball b

, m subscript a equals 2 m subscript
b. when the two balls reach the ground, how do their kinetic energies compare?
Physics
2 answers:
Sindrei [870]3 years ago
8 0
The mass of ball a is twice the mass of ball b:
m_a = 2 m_b
This means that the initial potential energy of ball a (U_a = m_a gh=2 m_b gh) is twice the potential energy of ball b (U_b = m_b  g h):
U_a = 2 U_b
When the two balls reach the ground, the potential energy of each ball has converted into kinetic energy (since now their altitude is h=0), because the total mechanical energy of each ball must be  conserved. Therefore:
K_a = U_a
K_b = U_b
and so the kinetic energy of ball a must be twice the kinetic energy of ball b:
K_a = 2 K_b
statuscvo [17]3 years ago
6 0

Answer:

5.5 m/s

Explanation:

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Answer:

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Explanation:

Data;

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a) = work = force * distance

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a = v² / 2s

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C). The work stops when the work done to raise the spring equals the work done to stop it by the spring

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516705 = 8.0*10⁴x²

X² = 516705 / 8.0*10⁴

X² = 6.46

X = √(6.46)

X = 2.54m

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3 0
3 years ago
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Answer:

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Explanation:

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Galina-37 [17]

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Explanation:

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