Two balls of equal size are dropped from the same height from the roof of a building. the mass of ball a is twice that of ball b
2 answers:
The mass of ball a is twice the mass of ball b:
This means that the initial potential energy of ball a (
) is twice the potential energy of ball b (
):
When the two balls reach the ground, the potential energy of each ball has converted into kinetic energy (since now their altitude is h=0), because the total mechanical energy of each ball must be conserved. Therefore:
and so the kinetic energy of ball a must be twice the kinetic energy of ball b:
This means that the initial potential energy of ball a (
When the two balls reach the ground, the potential energy of each ball has converted into kinetic energy (since now their altitude is h=0), because the total mechanical energy of each ball must be conserved. Therefore:
and so the kinetic energy of ball a must be twice the kinetic energy of ball b:
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Answer:
Explanation:
Given that,
The compression in the spring, x = 0.0647 m
Speed of the object, v = 2.08 m/s
To find,
Angular frequency of the object.
Solution,
We know that the elation between the amplitude and the angular frequency in SHM is given by :
A is the amplitude
In case of spring the compression in the spring is equal to its amplitude
So, the angular frequency of the spring is 32.14 rad/s.