Parallel Resistor Equation
If the two resistances or impedances in parallel are equal and of the same value, then the total or equivalent resistance, RT is equal to half the value of one resistor. That is equal to R/2 and for three equal resistors in parallel, R/3, etc.
It’s true hope this helps you
Answer:
Hello your question is poorly written below is the well written question and the diagram attached to your question is attached below as w ell
A solid steel shaft ABCDE turns freely in bearings at points A and E. The shaft is driven by the gear at C, which applies a torque T2 325 lb-ft. Gears at B and D are driven by the shaft and have resisting torques T1 200 lb-ft and T3 125 lb-ft, respectively. Segments BC and CD have lengths LBC 20 in. and LCD 15 in. and the shear modulus G 11,600 ksi. Determine the minimum required diameter (d) of the shaft if the allowable shear stress t a 56 ksi. Also calculate the angle of twist between gears B and D.
answer :
a) d ≈ 12.7 inches
b) ∅bc = 1.62 * 10^-3 rad
∅cd = 7.59 * 10^-4 rad
Explanation:
Given data :
G = 11600 ksi
Ta11 = 6 ksi
<u>a) determine the minimum required diameter </u>
Apply the relation below
Toc / Ip = Ta11 / R = G*∅ / L
∴ Ip = Tbc * R / Ta11
π / 32 * (d)^4 = [ ( 200 * 12 ) * ( d/2 )] / 6
therefore : d = 12.7 inches
<u>b) determine angle of twist between gears B and D </u>
attached below is the detailed solution
) ∅bc = 1.62 * 10^-3 rad
∅cd = 7.59 * 10^-4 rad
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